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NARA [144]
3 years ago
8

Do reflections have the same orientation? In other words, if a shape is reflected, do both figures still have the same orientati

on?
Mathematics
1 answer:
melisa1 [442]3 years ago
4 0

Answer:

I think so.

Step-by-step explanation:

With letters, no, and some shapes would be reversed, like a triangle with lengths that are all different from eachother.

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PLEASE HELP!! DUE REALLY SOON (LINK)
andre [41]

Answer:

youngest=115

middle=150

elder=230

Step-by-step explanation:

let the youngest be x

the middle will be x+35

the oldest will be 2x

x+x+35+2x=495

4x+35=495

4x=495-35

4x=460

x=115

since the youngest is x,the money he will receive is $115.

the middle will be x+35 which is equal to 115+35=$150.

lastly the oldest will be 2x which is equal to 2×115=$230.

7 0
3 years ago
Read 2 more answers
Will mark as brainliest plz help <br>The value of (17+ V2)(17– V2) is<br>​
MAXImum [283]

Using formula a^2- b^2 = (a-b)(a+b)

(17 + v ^{2} )(17 -  {v}^{2} ) \\  = (17)^{2}  -  {(v ^{2} )}^{2} \\  = 289 -  {v}^{4}

6 0
3 years ago
Read 2 more answers
A candle is lit and the length of the burning candle changes at a constant rate of -1.6 inches per hour. 3 hours after the candl
Gnesinka [82]

Answer: The length of the candle was 13.5 inches before it was lit.

Step-by-step explanation:

Let the length of candle in the beginning be c.

Constant rate of change in length of candle=  -1.6 inches per hour

Since rate of change is constant so the length of candle can be represented by a linear function [Linear function has constant rate of change.]

Linear function : f(x)= mx+c , where x= independent variable.

m= constant rate of change and c= initial value of function.

Let x = Number of hours after the candle was lit.

Put m=  -1.6 , x= 3 and f(x)= 8.7 , we get

8.7=-1.6(3)+c\\\\ 8.7= -4.8+c\\\\ c=8.7+4.8=13.5

Hence, the length of the candle was 13.5 inches before it was lit.

5 0
4 years ago
Pairs of jeans?
dangina [55]

Answer:

$534

Step-by-step explanation:

89*2=178

178+89(4)=534

3 0
3 years ago
Read 2 more answers
The manager of an accounting department wants to form a two
Y_Kistochka [10]

Answer: 153

Step-by-step explanation:

When we have a group of N elements, the total number of combinations of K elements ( K ≤ N) is:

C (N, K) = \frac{N!}{(N-k)!*K!}

Where N! = N*(N - 1)*(N - 2)*...*2*1

In this case, we have a group of 18 people (then N = 18) and we want to see how many different combinations of 2 we can make (K = 2).

Using the above equation we get:

C(18, 2) = \frac{18!}{(18 - 2)!*2!}  = \frac{18!}{16!*2!} = \frac{18*17}{2}  = 9*17 = 153

There are 153 different ways in which the manager can do this.

5 0
3 years ago
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