<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
Except there are values you want to substitute into the expression, this is what your answer looks like:
16 it is as easy as multiplying
Answer:
Surface Area = 82.8 square meters
Volume = 37.96 cubic meters
Surface area:
6 × 2 = 12
9 × 2 = 18
8.8 × 6 = 52.8
12 + 18 + 52.8 = 82.8
Volume:
6 × 2 × 9.49 = 113.88
113.88 ÷ 37.96
