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2 years ago

What is the value of 11.5

Mathematics

1 answer:

vodomira [7]2 years ago

6 0

Answer:

I don't understand what you are looking for

Step-by-step explanation:

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How many times larger is 3 x 10 to the power of negative 5 end exponent than 6 x 10 to the power of negative 12 end exponent

valentinak56 [21]

For you to be able to answer this you might need a tall numberline

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2 years ago

the graph is _ throughout its domain and has _ at the x-axis because the value bx can get very close to 0 but never reach it

Lady_Fox [76]

Answer:

Increasing and an asympote

Step-by-step explanation:

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2 years ago

Read 2 more answers

The car is moving with a speed v0 = 48 mi/hr up the 4-percent grade, and the driver applies the brakes at point A, causing all w

lutik1710 [3]

Answer:

s = 0.2203 miles

Step-by-step explanation:

Given:

- The initial speed vo = 48 mi/hr

- The mass of the car m

- The coefficient of kinetic friction uk = 0.61

- The slope of the road 4-percent grade

Find:

Determine the stopping distance sAB. Repeat your calculations for the case when the car is moving downhill from B to A.

Solution:

- Apply the energy principle with work done against friction:

K.E_1 + P.E_1 = Wf + P_E_2 + K.E_2

- The final velocity of car is zero, K.E_2 = 0

The initial potential energy is set as zero, P.E_1 = 0

K.E_1 = Wf + P_E_2

0.5*m*vo^2 = Ff*s + m*g*h

Where, Ff is the frictional force:

Ff = uk*N

Where, N is the normal contact force between car and road. By equilibrium equation we have:

m*g*cos(θ) - N = 0

N = m*g*cos(θ)

Hence,

Ff = uk*m*g*cos(θ)

- The vertical distance travelled h is:

h = s*sin(θ)

- The energy equation is:

0.5*m*vo^2 = uk*m*g*cos(θ)*s + m*g*s*sin(θ)

0.5*vo^2 = uk*g*cos(θ)*s + g*s*sin(θ)

s*(uk*g*cos(θ) + g*sin(θ) ) = 0.5*vo^2

s = [0.5*vo^2 / (uk*g*cos(θ) + g*sin(θ) ) ]

- The slope = 4 / 100,

s = [0.5*48^2 / (0.61*8052.97*cos(2.29) + 8052.97*sin(2.29) ) ]

s = 0.2203 miles

3 0

3 years ago

Let v1=(3,5) and v2=(-4,7) Compute the unit vectors in the direction of |v1| and |v2|?

AleksandrR [38]

By definition, the unit vector of v = (a,b) is
$\hat{v} = \frac{\vec{v}}{|v|}$

Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
(3,5)/√[3² + 5²]
= (3,5)/√34

The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65

Answer:
The unit vector of v₁ in the direction of |v₁} is $( \frac{3}{\sqrt{34}} , \frac{5}{\sqrt{34}} )$
The unit vector of v₂ in the directin of |v₂| is
$( \frac{-4}{\sqrt{65}} , \frac{7}{\sqrt{65}} )$

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3 years ago

The measure of the missing angle is ?

Cerrena [4.2K]

X = 97

Working on other question.

3 0

3 years ago