Answer:
Step-by-step explanation:
Isolate the term of n from one side of the equation.
<h3>n-1/8=3/8</h3>
<u>First, add by 1/8 from both sides.</u>
n-1/8+1/8=3/8+1/8
<u>Solve.</u>
<u>Add the numbers from left to right.</u>
3/8+1/8=4/8
<u>Common factor of 4.</u>
4/4=1
8/4=2
<u>Rewrite as a fraction.</u>
=1/2
n=1/2
<u>Divide is another option.</u>
1/2=0.5
n=1/2=0.5
- <u>Therefore, the final answer is n=1/2=0.5.</u>
I hope this helps you! Let me know if my answer is wrong or not.
Answer:
16n + 18
Step-by-step explanation:
-5n + 3(6 + 7n)
Distributing the 3 over the parenthesis:-
= -5n + 3*6 + 3*7n
= -5n + 18 + 21n
= 16n + 18
I'm pretty sure it would just be like this If p then q
Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.