Answer:
the cost function is Cost=7000 m*$ /R + 50.265 $/m² * R²
Step-by-step explanation:
then the cost function is
Cost= cost of side area+ cost of top + cost of bottom = 2*π*R*L * 5$/m² +
π*R² * 8$/m² + π*R² * 8$/m²
since the volume V is
V=π*R²*L → V/(π*R²)=L
then
Cost=2*π*R*V/(π*R²) * 5$/m² + π*R² * 8$/m² + π*R² * 8$/m²
replacing values
Cost=2*700 m³ /R * 5$/m² + π*R² * 16$/m² = 7000 m*$ /R + 50.265 $/m² * R²
thus the cost function is
Cost=7000 m*$ /R + 50.265 $/m² * R²
Answer:
x=-5, x=9
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
equate to zero
so
substitute in the formula
therefore
The solutions are x=-5, x=9
Xy=-36
x+y=-3
x= -36/y
-36/y + y = -3
-36 + y^2 = -3y
y^2 +3y -36 = 0
I think you have to use quadratic formula to find the 2 values of y and then plug in for x
Let x be the third side of this triangle. We can't find a single value for x because x can range between a boundary of values. The interval for x is
38-25 < x < 38 + 25
13 < x < 63
So as long as x is between 13 and 63 (ignore the endpoints themselves), then we have a valid possible third side length. The values that fit this description are...
14, 17, 19.4, 46
which are the answers
the other values (13, 63, 71) are outside of the interval mentioned
The answer is 6
270 students divided by 45 chaperones equals 6 per chaperone
