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Nimfa-mama [501]
3 years ago
11

Create a 10 question survey with quantitative variables (number) on a topic you are interested in. Think of questions where 0 is

dislike there is a scale to 4- like. Another way to do this is using 0-never, 1 sometimes, 2 frequently, and 3 always. Administer the survey to a minimum of 10 people. Analyze your data for the mean, median, and mode of each questions. Create a visual from this chapter: bar graph, box and whisker plot, histogram, stem and leaf plot. etc. Compile the information into a slide presentation, of at least 5 slides, to present at the next town hall. The presentation should present: the mean, median, and mode of each question, the visual of the data, and conclusions based on the statistics you found in the survey.
Mathematics
1 answer:
Ugo [173]3 years ago
3 0

Answer:

this is too much to ask for

Step-by-step explanation:

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Yeahhh im pretty not smart
Lerok [7]

Answer:

6 units between a and c then from c to b is 3

Step-by-step explanation:

7 0
3 years ago
WILL UPVOTE!<br> solve and show all steps please (√25+√9)^2
dalvyx [7]
The square root of 25 = 5
the square root of 9 = 3

5 + 3 = 8

8^2 = 64
5 0
3 years ago
Read 2 more answers
25,-9,18,1 ,-7,-20,10,14,-4,0,12,-14 out the following integers from least to greatest
Trava [24]

Answer:

-20, -14, -9, -7, -4, 0, 1, 10, 12, 14, 18, 25

Step-by-step explanation:

7 0
4 years ago
Round 363 to the nearest ten and hundred
IRISSAK [1]
Its 400 because 363 is closer to 400 than 300
3 0
4 years ago
Read 2 more answers
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

                                    =(0.70)^{3}\\=0.343

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

                                   =1-0.343\\=0.657

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

                         = P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

                              + P (Only 3rd vehicle passes)

                       =(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

                                                       + P (0 vehicles passes)

                                              =0.189+(0.30\times0.30\times0.30)\\=0.216

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0
3 years ago
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