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statuscvo [17]
3 years ago
9

Now that you know the vertex, find the y-values that pair with a few x-values that are less than 2 and a few that are greater th

an 2.
Plsssss help!!!!!!!

Mathematics
1 answer:
Fantom [35]3 years ago
5 0
Y when x=0: 3
y when x=1: 2
y when x=3: 2
y when x=4: 3
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I probably should've learned this but can someone help me I'm desperate!
lesantik [10]
Sorry I don't have enough time to deal with this problems, I believe that by using this formula you will easily come out with your answer. In the first one that has all sides you must use the law of cosines. Here is the formulas . Keep it because it is very helpful

6 0
3 years ago
Kim rolls a dice and flips a coin
KATRIN_1 [288]

Since, both the events are independent.

So, P(A+B) = P(A)×P(B)

a) P( Head & Getting a 2 ) = P( head ) × P( Getting a 2 )

=\dfrac{1}{2}\times \dfrac{1}{6}\\\\=\dfrac{1}{12}

b) P( Even number & Tail ) = P( Even number ) × P( Tail )

=\dfrac{3}{6}\times \dfrac{1}{2}\\\\= \dfrac{1}{4}

Hence, this is the required solution.

6 0
3 years ago
A piece of lumber is 2 1/4 feet long is to be cut into 3 equal pieces. How long will each piece of cut wood be? Give the measure
abruzzese [7]
2 1/4 = 2 times 4 + 1 = 9/4 times by 1/3 = 4/12 simplest form is 3/4 inches
7 0
3 years ago
Read 2 more answers
The rectangle is being reduced by a scale factor of 3/4 what is the area of the new image
DENIUS [597]

Answer:

big money

Step-by-step explanation:

4 0
3 years ago
Answer these In scientific notation with work shown, adding scientific notation.
vichka [17]

Answer:

1.  9.9 \times 10^{-1}   + 5.2 \times 10^{-2} = 104.2 \times 10^{-2}

2. 3.24 \times 10^{5}   + 8.3 \times 10^{1} =32408.3 \times 10^{1}

3.1.24 \times 10^{0}   + 5 \times 10^{-1} = 13.64 \times 10^{-1}

Step-by-step explanation:

1)  9.9 \times 10^{-1}   + 5.2 \times 10^{-2}

Now,  9.9 \times 10^{-1}  =  99 \times 10^{-2}  

So,  99 \times 10^{-2}   + 5.2 \times 10^{-2}  =  104.2 \times 10^{-2}  

2. 3.24 \times 10^{5}   + 8.3 \times 10^{1}

Now,  3.24 \times 10^{5}  =  32400 \times 10^{1}  

So,  32400 \times 10^{1} + 8.3 \times 10^{1}  =  32408.3 \times 10^{1}  

3.1.24 \times 10^{0}   + 5 \times 10^{-1}

Now,  1.24 \times 10^{0}  =  12.4 \times 10^{1-}  

So,  1.24 \times 10^{0}  + 12.4 \times 10^{1-}  =  13.64 \times 10^{-1}  

8 0
4 years ago
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