Does the equation -x+4y=-2 represent a direct variation. if so what is the constant variation

Mathematics

1 answer:

Harrizon [31]2 years ago

5 0

Answer:

Yes it represents.

Variation tax = 0,25

Step-by-step explanation:

Direct variation is the name we gave to the rate of change of a first degree function.

A first degree generic function is:

y = f(x) = ax + b

Now observe the question's function:

- x + 4y = -2

4y = x - 2

y = 1/4x - 2/4

y = f(x) = 0,25x - 0,5

0,25 is our constant variation, because any number that x assume will be multiplied by 0,25.

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In the right triangle shown Ac=BC and AB=6 to the square root of 3, how long are each of the legs

Inga [223]

Answer:

6 units

Step-by-step explanation:

I will just assume that you made a typo when typing the question when saying AB is 6√3. Here is the solution if AB = 6√2.

Since it is given that ABC is a right triangle and x labels each of the legs, the triangle is a right isoceles triangle.

Now we can use the right isoceles triangle theorem to solve the problem. This theorem states that if a leg is "x" in a right isoceles triangle, then the hypotenuse is equal to x√2.

Here, the hypotenuse is equal to 6√2. To figure out the legs, you need to solve the equation 6√2 = x√2. It is solved here:

6√2 = x√2 (Divide by √2)

x = 6

The length of the legs are 6 units.

4 0

2 years ago

Pls help sixowiskosixo

erma4kov [3.2K]

The given question is a quadratic equation and we can use several methods to get the solutions to this question. The solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

<h3>Quadratic Equation</h3>

Quadratic equation are polynomials with a second degree as it's highest power.

An example of a quadratic equation is

$y = ax^2 + bx + c$

The given quadratic equation is $24x^2 + 2x = 15$

Let's rearrange the equation

$24x^2 + 2x = 15\\24x^2 + 2x - 15 = 0$

This implies that

a = 24
b = 2
c = -15

The equation or formula of quadratic formula is given as

$y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}$

We can substitute the values into the equation and solve

$y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}\\y = \frac{-2 +- \sqrt{2^2 -4 * 24 * (-15)} }{2*24} \\y = \frac{-2+-\sqrt{4+1440} }{48} \\y = \frac{-2+-\sqrt{1444} }{48} \\y = \frac{-2+- 38}{48} \\y = \frac{-2+38}{48} \\y = \frac{3}{4}\\ \\or\\y = \frac{-2-38}{48} \\y = \frac{-40}{48} \\y = -\frac{5}{6}$