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3 years ago

Does the equation -x+4y=-2 represent a direct variation. if so what is the constant variation

Mathematics

1 answer:

Harrizon [31]3 years ago

5 0

Answer:

Yes it represents.

Variation tax = 0,25

Step-by-step explanation:

Direct variation is the name we gave to the rate of change of a first degree function.

A first degree generic function is:

y = f(x) = ax + b

Now observe the question's function:

- x + 4y = -2

4y = x - 2

y = 1/4x - 2/4

y = f(x) = 0,25x - 0,5

0,25 is our constant variation, because any number that x assume will be multiplied by 0,25.

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Need Help with this. 4(v+4)-7v

Zolol [24]

Answer:16-3v

Step-by-step explanation:

Take off the brackets by multiplying the terms inside the bracket by 4,

4v+16-7v

Simplify

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2 years ago

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- Which product is greater, (-4) • (-6) or<br> (-7).(-8)? Explain

mr Goodwill [35]

Answer:

(-7)*(-8)

Step-by-step explanation:

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2 years ago

Which points are exactly 10 units from the point (–8, –2)? Check ALL that apply.

Archy [21]

Answer:

The points that are exactly 10 units from the point (–8, –2) are (2, –2) and (–8, 8).

Step-by-step explanation:

The distance formula is;

d= $\sqrt{( x_{2}-x_{1} )^{2}-(y_{2} -y_{1} )^{2} }$

So for distance between: (–8, –2) and (2, –2) is:

d= $\sqrt{( 2-(-8))^{2}-(-2 -(-2) )^{2} }$

d= $\sqrt{100}$

d= 10 unit

Similarly for distance between: (–8, –2) and (–8, 8) is,

d= $\sqrt{( -8-(-8))^{2}-(8 -(-2) )^{2} }$

d= $\sqrt{100}$

d= 10 unit

6 0

3 years ago

Which function in Excel is used to perform a test of independence? a. T.TEST b. CHISQ.TEST c. NORM.S.DIST d. Z.TEST

denis23 [38]

Answer:

b. CHISQ.TEST

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

The statistic is given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}$

In order to calculate the p value we need to have in count the degrees of freedom , on this case $df=(rows-1)(#cols-1)$ . And we can calculate the p value would be given by:

$p_v =P(\chi^2 >\chi^2_{calc})$

But the correct comand is given by:

b. CHISQ.TEST(Actual range, Expected range)

We just need to put in one column the Observed values and in other the expectec values.

3 0

3 years ago