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2 years ago

9

Please help me ( show ur work it’s multiple choice ):)

1 answer:

GaryK [48]2 years ago

7 0

B=29.4 !!!!!!!! this how i do it

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Question 23 geometry

Vadim26 [7]

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3 years ago

Find the Answer to <br><br><br>y = [???]

marishachu [46]

Answer:

Y=60°

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1 year ago

Please help asap

ElenaW [278]

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3 years ago

Read 2 more answers

A room contains three urns: u1, u2, u3. u1 contains 3 red and 2 yellow marbles. u2 contains 3 red and 7 yellow marbles. u3 conta

Archy [21]

Answer:

$\dfrac{11}{30}$

Step-by-step explanation:

Urn U1: 3 red and 2 yellow marbles, in total 5 marbles.

The probability to select red marble is $\dfrac{3}{5}=0.6.$

Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

The probability to select red marble is $\dfrac{3}{10}=0.3.$

Urn U1: 1 red and 4 yellow marbles, in total 5 marbles.

The probability to select red marble is $\dfrac{1}{5}=0.2.$

The probability to choose each urn is the same and is equal to $\frac{1}{3}.$

Thus, the probability that the marble is red is

$\dfrac{1}{3}\cdot 0.6+\dfrac{1}{3}\cdot 0.3+\dfrac{1}{3}\cdot 0.2=\dfrac{1.1}{3}=\dfrac{11}{30}.$

4 0

3 years ago

2. Determine the sum of the first 400 ODD numbers.<br><br>

il63 [147K]

Odd numbers take the form $2n-1$ , where $n\ge1$ is an integer. When $n=400$ , the last odd number would be 799. So we're adding

$S=1+3+5+\cdots+795+797+799$

By reversing the order of terms, we have

$S=799+797+795+\cdots+5+3+1$

and we can pair up terms in both sums at the same position to write

$2S=(1+799)+(3+797)+(5+795)+\cdots(795+5)+(797+3)+(799+1)$

so that we are basically adding 400 copies of 800, and from there we can find the value of the sum right away:

$2S=400\cdot800\implies S=160,000$

###

We could also make use of the formulas,

$\displaystyle\sum_{i=1}^n1=n$

$\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2$

We have

$S=\displaystyle\sum_{i=1}^{400}(2i-1)=2\sum_{i=1}^{400}i-\sum_{i=1}^{400}1=400(400+1)-400=400^2=160,000$

3 0

3 years ago