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n200080 [17]
3 years ago
5

Types of cybercrime​

Computers and Technology
2 answers:
sergij07 [2.7K]3 years ago
8 0

Answer:

Types of cybercrime

Here are some specific examples of the different types of cybercrime:

*Email and internet fraud.

*Identity fraud (where personal information is stolen and used).

*Theft of financial or card payment data.

*Theft and sale of corporate data.

*Cyberextortion (demanding money to prevent a threatened attack).

*Ransomware attacks (a type of cyberextortion).

*Cryptojacking (where hackers mine cryptocurrency using resources they do not own).

*Cyberespionage (where hackers access government or company data).

Most cybercrime falls under two main categories:

*Criminal activity that targets

*Criminal activity that uses computers to commit other crimes.

Explanation:

Rufina [12.5K]3 years ago
7 0
-Email and internet fraud.
-Identity fraud (where personal information is stolen and used).
-Theft of financial or card payment data.
-Theft and sale of corporate data.
-Cyberextortion (demanding money to prevent a threatened attack).
-Ransomware attacks (a type of cyberextortion).
-Cryptojacking (where hackers mine cryptocurrency using resources they do not own).
-Cyberespionage (where hackers access government or company data)
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CODING TIME
Fynjy0 [20]

Answer:

food_list = ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea']

one_more = ['meat']

extend_list = food_list + one_more

print(extend_list)

Output : ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea', 'meat']

food_list.append('milk')

print(food_list)

Output : ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea', 'milk']

food_list.insert(0, 'cake')

print(food_list)

Output : ['cake', 'rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea']

flowers = ['rose', 'hibiscus', 'lily']

flowers.remove('rose')

print(flowers)

Output : ['hibiscus', 'lily']

To remove rose using pop()

flowers.pop(0)

Explanation:

The + operator and append method adds elements to the end of an existing list item.

The insert method adds element at the specified index

Remove method deletes element by stating the name of the element to be deleted while pop deletes element using the index value of the element.

7 0
3 years ago
Look at the pic. I know what girls be going through like us girls aren't toys. Please stop, please.
mixas84 [53]

Answer:

No need to be overly-sensitive, brainly deleted that question

If no one joins then its not a problem

6 0
2 years ago
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Uses computer resources from multiple locations to solve a common problem.
Lynna [10]

Answer:

Distributed Computing is used to solve common problem from multiple locations at different locations.

Explanation:

It is the architecture of processor, that is used to combine the different resources of computer from different domain to solve the common problem.

It allows us resource sharing such as hardware and software that are connected to the computer.

Examples

Following are the examples of Distributed computing.

  1. Telecommunication Network
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8 0
4 years ago
class llist { private: record * start; char filename[16]; int readfile(); int writefile(); record * reverse(record * ); void cle
Sophie [7]

Answer:

See Explaination

Explanation:

#include <cstdlib>

#include <iostream>

#include <iomanip>

#include <fstream>

#include <string>

#include <sstream>

using namespace std;

struct Person

{

string name;

string addr;

string phone;

string id;

};

const int MAX_SIZE = 8;

void addData(Person list[], int& size);

void dispData(const Person list[], int size);

void delData (const Person list[], int size);

void saveFile(const Person list[], int size);

void openFile(Person list[], int& size);

char getMenuResponse();

int main(int argc, char *argv[])

{

Person contactList[MAX_SIZE];

int numOfRecs = 0;

bool run = true;

do

{

cout << "Address Book - " << numOfRecs << " Number of Contacts" << endl;

switch ( getMenuResponse() )

{

case 'A': addData(contactList, numOfRecs); break;

case 'D': dispData(contactList, numOfRecs); break;

case 'T': delData(contactList, numOfRecs); break;

case 'O': openFile(contactList, numOfRecs); break;

case 'S': saveFile(contactList, numOfRecs); break;

case 'Q': run = false; break;

default : cout << "That is NOT a valid choice" << endl;

}

} while (run);

cout << endl << "Program Terminated" << endl;

return EXIT_SUCCESS;

}

void addData(Person list[], int& size)

{

Person tmp;

char response;

char str[256];

if (size < MAX_SIZE) {

system("cls");

cout << "Enter Contact Information" << endl << endl;

cout << "Name: ";

cin.getline(str, 256, '\n');

tmp.name = str;

cout << endl;

cout << "Address: ";

cin.getline(str, 256, '\n');

tmp.addr = str;

cout << endl;

cout << "Phone Number: ";

cin.getline(str, 256, '\n');

tmp.phone = str;

cout << endl;

cout << "E-mail id Address: ";

cin.getline(str, 256, '\n');

tmp.id = str;

cout << endl;

cout << "Add Contact to Address Book? (y/n) ";

cin >> response;

if (toupper(response) == 'Y')

list[size++] = tmp;

} else {

cout << "Sorry, Address Book is currently full." << endl;

system("pause");

}

system("cls");

}

void dispData(const Person list[], int size)

{

system("cls");

if(size < 1)

{

cout << "Nothing to display" << endl;

} else {

cout << "Contacts :" << endl << endl;

cout << fixed << setprecision(2);

cout << "Contact Name Address Phone No. ID" << endl;

cout << left;

for (int i = 0; i < size; i++)

{

cout << setw(10) << list[i].name << right

<< setw(10) << list[i].addr<<right

<< setw(10) << list[i].phone<<left

<< setw(15) << list[i].id<<left<<endl;

}

cout << right << setw(3) << size;

cout << " Contacts"<< endl;

}

system("PAUSE");

system("cls");

}

void delData(const Person list[],int size) {

vector<Person> :: iterator vItr = Contact.begin();

while (vItr != Contact.end() )

{

if (vItr->Name == Name)

{

vItr = Contact.erase (vItr);

break;

}

else

vItr++;

}

void saveFile(const Person list[], int size) {

string fileName;

ofstream outfi;

cout<<"Enter file name: ";

getline(cin,fileName);

outfi.open(fileName.c_str());

if (!outfi.fail()) {

system("cls");

cout << "Saving Address Book to the disc ";

for(int i = 0; i < size; i++) {

outfi << list[i].name << ';'

<< list[i].addr<< ';';

if (i < size-1) outfi << endl;

}

cout << endl << size << " Address Book in the disc." << endl;

outfi.close();

system("PAUSE");

system("cls");

}

else {

cout << "ERROR: problem with file" << endl;

system("PAUSE");

system("cls");

}

}

void openFile(Person list[], int& size)

{

ifstream infi("AddressBook.txt");

string str;

stringstream strstrm;

if (!infi.fail()) {

system("cls");

cout << "Reading Address Book from the disc ";

size = 0;

while(!infi.eof() && size < MAX_SIZE)

{

getline(infi, str, ';');

list[size].name = str;

getline(infi, str, ';');

strstrm.str(""); strstrm.clear();

strstrm << str;

strstrm >> list[size].addr;

}

cout << endl << size << " read contacts from the disc." << endl;

system("PAUSE");

system("cls");

}

else {

cout << "ERROR :file not accepted" << endl;

system("PAUSE");

system("cls");

}

}

char getMenuResponse()

{

char response;

cout << endl << "take chioce" << endl

<< "(A)dd contact, (D)isplay contact0, (O)pen File, (S)ave File, (Q)uit" << endl

<< "> ";

cin >> response;

cin.ignore(256, '\n');

return toupper(response);

}

8 0
3 years ago
What should Kenny do in the following scenario? To hide a toolbar on his taskbar, Kenny right-clicks in an empty space on the to
Georgia [21]

Answer:

Kenny should right-click the taskbar, not the toolbar.

Explanation:

Toolbars on Window’s taskbar are special applications that show on the bottom right of a Desktop display screen by default. The default toolbar options include Desktop, Links, Address, and any other custom toolbars added by the user. To remove or hide a toolbar, Kenny should right click on the taskbar, click on toolbars, and click to activate or untick to hide or the toolbar.

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