Answer:
The solution code is written in Python.
- def mult2_diff(lst):
- num_list = []
-
- for x in lst:
- num_list.append(x * 2)
-
- diff = num_list[0]
- for i in range(1, len(num_list)):
- diff = diff - num_list[i]
-
- print(diff)
Explanation:
Firstly, based on the requirement stated in the question, define a function <em>mult2_diff() </em>that takes one argument, <em>lst</em>, which is a list of numbers (Line 1).
This function is expected to multiply each number in the list by two and then followed with computing the difference. To do so, let's try to attempt the first function task, multiplying numbers. Create a new list, num_list, to hold the multiplied numbers (Line 2). Use a for loop to traverse through each number in the input list, <em>lst</em>, and multiply each of them by two and add it to the <em>num_list </em>(Line 4-5).
To attempt the second function task, create another variable, <em>diff</em>, to hold the value of calculated difference between the numbers in the <em>num_list</em>. Initialize <em>diff </em>with the first number in the <em>num_list</em>. Use a another for-loop to traverse through each number in the num_list starting with second index, <em>1</em>, and calculate the difference between the <em>diff </em>and the current number extracted from the <em>num_list </em>through indexing.
At last print the output of <em>diff</em> (Line 11).
He is a victim of plagiarism.
Plagiarism is when someone steals someone else's work, to help benefit themselves. Taking credit for the other person work.
Hope this helps!
Answer:
D
Explanation:
The answer is D because if you're looking for lightweight materials, you'll be dealing with chemistry, and chemistry is sience.
Answer:
They are both ways to identify assets (e.g., persons, animals, objects).
Explanation:
A barcode is a bit of information (usually a number) printed as a line or block pattern on a surface (e.g., a sticker).
An RFID is a bit of computer memory with an antenna.
Both can be read with the appropriate scanner device.
