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eimsori [14]
3 years ago
12

You have a Nano Server named Nano1. Which cmdlet should you use to identify whether the DNS Server role is installed on Nano1

Computers and Technology
1 answer:
bija089 [108]3 years ago
5 0

Answer:

The correct solution will be "Get-Package".

Explanation:

  • The accreditation property defines a domain as well as client initials with computer authorizations for executing commands. Mostly on the virtual device, the argument ScriptBlock executes the Get-Package cmdlet.
  • This order obtains from some kind of special introductory commercial software downloaded on either the user's computer.
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T F The exit function can only be called from main .
ElenaW [278]

Answer:

FALSE

Explanation:

The exit function is used to terminate or halt the process.

Syntax-

            void exit(int status)  

Exit function (exit()) can be used in any function not only main() and it will terminate your whole process.

<u></u>

<u>Example-</u> C Program

#include<stdio.h>

#include <stdlib.h>  

//  function declaration

float exitexample ( float x );                                

// Driver program

int main( )                

{

 float a, b ;

 printf ( "\nEnter some number for finding square \n");

  scanf ( "%f", &a ) ;

 // function call

 b = exitexample ( a ) ;                      

 printf ( "\nSquare of the given number %f is %f",a,b );  

/*This will not printed as exit function is in exitexample() function*/

}

float exitexample ( float x )   // function definition  

{

 exit(0);    //exit function

   float p ;

  p = x * x ;

return ( p ) ;

}

5 0
4 years ago
What are the three primary separation of concerns on the client-side of a dynamic web application? (Check all that apply)
nlexa [21]

Answer:

Behaviour

Style

Structure

Explanation:

Above are the three primary separation of concerns for a web application at client side.

Structure --> we can define the structure of the application at client side using HTML

style-->style is used to give some styling information like font,color,headings so on at client side .In general we use CSS to do this at client side

Behaviour--> it actually defines the functionality of the elements at client side like when we click button what it should do.We will use JavaScript to define the behaviours at client side

7 0
3 years ago
What happens if you create multiple accounts just to get points faster?
balandron [24]
I don’t think it will work sadly. You can probably accumulate points though on your pre existing account. Hope that helps!
8 0
3 years ago
Please help!
Darya [45]
The answer would be A.) Web pages provide information, while web applications allow the user to do something. a web page is for relaying information. (you can relate this to a book. a page in a book gives you information.) while an application allows you to perform an action.
4 0
3 years ago
Read 2 more answers
12.2 Sort an array in ascending order Write a program that gets a list of integers from input, and outputs the integers in ascen
notsponge [240]

Answer:

Explanation:

The following code is written in Java, it asks the user for the number of inputs that will be made and then the inputs. These inputs are placed into an array. Then the array is sorted and printed out to the terminal.

public static void sortArrayList() {

           ArrayList<Integer> sortedList = new ArrayList();

           Scanner input = new Scanner(System.in);

           System.out.println("Enter number of digits in Array");

           int numberOfInputs = input.nextInt();

           for (int i = 0; i < numberOfInputs; i++) {

                   System.out.println("Enter a number");

                   sortedList.add(input.nextInt());

           }

           int n = sortedList.size();

           for (int i = 0; i < n; i++)

               for (int j = 0; j < n-i-1; j++)

                   if (sortedList.get(j) > sortedList.get(j + 1))

                   {

                       // swap arr[j+1] and arr[j]

                       int temp = sortedList.get(j);

                       sortedList.set(j, sortedList.get(j + 1));

                       sortedList.set(j + 1, temp);

                   }

           for (int x : sortedList) {

               System.out.println(x);

           }

       }

7 0
3 years ago
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