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3 years ago

Fill in the blank with a number to make the expression a perfect squared… W squared + 6w +

Mathematics

1 answer:

Neporo4naja [7]3 years ago

8 0

Answer:

$(a+b)^{2} =a^{2}+2ab+b^{2}$

$(1)w^{2}+2(3)(1)w+3^{2}\\\\=(w+3)^{2}\\\\=(w+3)(w+3)$

Therefore, $w^{2} +6w+9$ makes a perfect squared.

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Saiges spaceship traveled 588 kilometers in 60 seconds. Determine whether or not each spaceship trip below has the same speed as

Fiesta28 [93]

Answer:

Part 1) 441km in 45s --> Has the same speed as Saige's spaceship

Part 2) 215km in 25s --> Does not have the same speed as Saige's spaceship

Part 3) 649km in 110s --> Does not have the same speed as Saige's spaceship

Step-by-step explanation:

The complete question is

Saige's spaceship traveled 588 kilometers in 60 seconds.

Determine whether or not each spaceship trip below has the same speed as Saige's spaceship.

441km in 45s

215km in 25s

649km in 110s

we know that

The speed is equal to divide the total distance traveled by the total time

In this problem we have that

The speed of Saiges spaceship is equal to

$\frac{588}{60}=9.8\ \frac{km}{sec}$

case 1) we have

441km in 45s

Find out the speed of the spaceship trip

$\frac{441}{45}=9.8\ \frac{km}{sec}$

Compare the speed of the spaceship trip with the speed of Saiges spaceship

$9.8\ \frac{km}{sec}=9.8\ \frac{km}{sec}$

therefore

Has the same speed as Saige's spaceship

case 2) we have

215km in 25

Find out the speed of the spaceship trip

$\frac{215}{25}=8.6\ \frac{km}{sec}$

Compare the speed of the spaceship trip with the speed of Saiges spaceship

$8.6\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}$

therefore

Does not have the same speed as Saige's spaceship

case 3) we have

649km in 110s

Find out the speed of the spaceship trip

$\frac{649}{110}=5.9\ \frac{km}{sec}$

Compare the speed of the spaceship trip with the speed of Saiges spaceship

$5.9\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}$

therefore

Does not have the same speed as Saige's spaceship

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