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Monica [59]
3 years ago
9

Fill in the blank with a number to make the expression a perfect squared… W squared + 6w +

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

(a+b)^{2} =a^{2}+2ab+b^{2}

(1)w^{2}+2(3)(1)w+3^{2}\\\\=(w+3)^{2}\\\\=(w+3)(w+3)

<u>Therefore, </u>w^{2} +6w+9<u> makes a perfect squared.</u>

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Can someone help me with this and explain it?
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Answer:

4 pizzas

Step-by-step explanation:

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Read 2 more answers
Rewrite the expression with a rational exponent as a radical expression.
Nuetrik [128]

Answer:

Rewriting the expression (3^\frac{2}{3})^\frac{1}{6} with a rational exponent as a radical expression we get \mathbf{\sqrt[9]{3} }

Step-by-step explanation:

We need to rewrite the expression (3^\frac{2}{3})^\frac{1}{6} with a rational exponent as a radical expression.

The expression given is:

(3^\frac{2}{3})^\frac{1}{6}

First we will simply the expression using exponent rule (a^m)^n=a^{mn}

(3^\frac{2}{3})^\frac{1}{6}\\=(3^\frac{2}{18})

As we know 2 and 18 are both divisible by 2, we can write

=(3^\frac{1}{9})

Now we know that a^\frac{1}{9}=\sqrt[9]{a}

Using this we get

=\sqrt[9]{3}

So, rewriting the expression (3^\frac{2}{3})^\frac{1}{6} with a rational exponent as a radical expression we get \mathbf{\sqrt[9]{3} }

3 0
3 years ago
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