Question

What substitution Should be used to re-write 26(x^3+1)^2-22(x^3+1)-3=0 as a quadratic function?

Answer 1

Answer:

$x^3+1$

Step-by-step explanation:

$26(x^3+1)^2-22(x^3+1)-3=0$

Comparing to

$A(u)^2+B(u)+C =0$

Where A,B,C are constants

You should see that we need to substitute the $x^3+1$ with u.