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ki77a [65]
2 years ago
5

Which expression is equivalent to 2^-3/2^-5

Mathematics
1 answer:
Aleks04 [339]2 years ago
3 0

Answer:

2^2

Step-by-step explanation:

2^-3/2^-5

We know that a^b / a^c = a^(b-c)

2^-3/2^-5 = 2^( -3 - -5) = 2^(-3+5) = 2^2

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Wild cats scored a total of 123 points. 67 points were scored in the first half. How many were scored in the second half?
Dima020 [189]
123-67=56 points. So, subtract and you get 56 points in the second half
7 0
3 years ago
A museum conducts a survey of its visitors in order to assess the popularity of a device which
Natali5045456 [20]

Answer:

i:

The appropriate null hypothesis is H_0: p \geq 0.2

The appropriate alternative hypothesis is H_1: p < 0.2

The p-value of the test is 0.1057 > 0.05, which means that there is not sufficient evidence that fewer than 20% of the museum visitors make use of the device, and so, it should not be withdrawn.

ii:

The p-value of the test is 0.1057

Step-by-step explanation:

Question i:

The device will be withdrawn if fewer than 20% of all of the museum’s visitors make use of it.

At the null hypothesis, we test if the proportion is of at least 20%, that is:

H_0: p \geq 0.2

At the alternative hypothesis, we test if the proportion is less than 20%, that is:

H_1: p < 0.2

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.2 is tested at the null hypothesis:

This means that \mu = 0.2, \sigma = \sqrt{0.2*0.8} = \sqrt{0.16} = 0.4.

The device will be withdrawn if fewer than 20% of all of the museum’s visitors make use of it. Of a random sample of 100 visitors, 15 chose to use the device.

This means that n = 100, X = \frac{15}{100} = 0.15

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.15 - 0.20}{\frac{0.4}{\sqrt{100}}}

z = -1.25

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.15, which is the p-value of z = -1.25.

Looking at the z-table, z = -1.25 has a p-value of 0.1057.

The p-value of the test is 0.1057 > 0.05, which means that there is not sufficient evidence that fewer than 20% of the museum visitors make use of the device, and so, it should not be withdrawn.

Question ii:

The p-value of the test is 0.1057

7 0
3 years ago
7x-3y = 10<br>-3x-8y= 5​
victus00 [196]
My answer would be y=-1
6 0
3 years ago
Solve the following system using the SUBSTITUTION method.<br> x - 3y = 2<br> 2x - 6y = 6
notka56 [123]

ANSWER:

  • x – 3y = 2 ...(1)
  • 2x – 6y = 6 ...(2)

On solving eq(1), we get

  • x – 2 = 3y
  • x – 2/3 = y

Plug the value of x in eq(2)

  • 2x – 6(x - 2/3) = 6
  • 2x – 2(x – 2) = 6
  • 2x – 2x + 4 = 6
  • 0 = 6 – 4
  • 0 ≠ 2

So, given system of equations is not correct.

6 0
3 years ago
Read 2 more answers
Suppose x=18,y=24, and z=30 in the figure, which is not drawn to scale. Determine the following values. Enter exact answers (as
sammy [17]

Answer:

See explanation

Step-by-step explanation:

cos(θ)= 18/30 = 3/5

sin(θ)= 24/30 = 4/5

tan(θ)= 24/18 = 4/3

cos(ϕ)= 24/30 = 4/5

sin(ϕ)= 18/30 = 3/5

tan(ϕ)= 18/24 = 3/4

3 0
3 years ago
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