All categories

3 years ago

A linear set of points with a unique starting point and extending infinitely in one direction what term matches the definition?

2 answers:

Rudiy273 years ago

6 0

A linear set of points with a unique starting point and extending infinitely in one direction is called a ray i.e., $\fbox{\begin\\\ \bf option (a)\\\end{minispace}}$ .

Further explanation:

To define a linear set of points with a unique starting point and extending infinitely in one direction, check for the options as shown below.

Option (a): Ray

A ray is defined as a line that starts with one fixed point and extends infinitely along the line from the fixed point.

This means if a linear set of points with a unique starting point and extending infinitely in one direction then it represents a ray.

Therefore, the option (a) is correct.

Option (b): Line

A line is defined as a straight path whose start and end points are on infinity that means a line extends infinitely in both directions.

Therefore, option (b) is incorrect.

Option (c): Segment

A segment is defined as a part of a line that has a start point and an end point.

This means if start and end point is known then the line is defined as a segment.

Therefore, option (c) is incorrect.

Option (d): Perpendicular bisector

A perpendicular bisector is defined as a line that cuts a line segment into two parts perpendicularly that means the angle between the line segment and perpendicular bisector is $90^{\circ}$ .

Therefore, option (d) is incorrect.

From the above options of a ray, a line, a segment and a perpendicular bisector we can conclude that given definition is equivalent to the definition of a ray.

Therefore, $\fbox{\begin\\\ \bf option (a)\\\end{minispace}}$ is correct.

Learn more:

1. Problem on the pair of undefined terms that is used to define a ray:

brainly.com/question/1087090

2. A problem on lines and angles: brainly.com/question/1953744

3. A problem on collinear points: brainly.com/question/5191341

Answer details:

Grade: Middle school.

Subject: Mathematics.

Chapter: Lines and angle.

Keywords: Line, line segment, ray, perpendicular, perpendicular bisector, point, parallel line, angle, angle bisector, perpendicular line, vertical line, horizontal line.

bija089 [108]3 years ago

5 0

Answer:- Option A "ray" is the right term which matches with the definition.

Explanation:-

A ray is a line that has one fixed endpoint, and extends infinitely along the line from the fixed endpoint.

Therefore, the term which matches with the given definition is "ray".

Thus A linear set of points with a unique starting point and extending infinitely in one direction is called a ray.

You might be interested in

Help me pleasee!!!!!!!!!!!!

tresset_1 [31]

Answer:

Step-by-step explanation:

Angles 1, 2, and 3 are supplementary (they add up to equal 180). If angles 1 and 3 are 20 each, then their sum in 40, making angle 2

180 - 40 = 140. If this central angle is 140 degrees, then the measure of the arc that it cuts off also measures 140 degrees. This is not to be confused with the arc length, which is not even remotely the same thing!

4 0

3 years ago

If 2tanA=3tanB then prove that, tan(A+B)= 5sin2B/5cos2B-1

Fed [463]

By definition of tangent,

tan(A + B) = sin(A + B) / cos(A + B)

Using the angle sum identities for sine and cosine,

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

yields

tan(A + B) = (sin(A) cos(B) + cos(A) sin(B)) / (cos(A) cos(B) - sin(A) sin(B))

Multiplying the right side by 1/(cos(A) cos(B)) uniformly gives

tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A) tan(B))

Since 2 tan(A) = 3 tan(B), it follows that

tan(A + B) = (3/2 tan(B) + tan(B)) / (1 - 3/2 tan²(B))

… = 5 tan(B) / (2 - 3 tan²(B))

Putting everything back in terms of sin and cos gives

tan(A + B) = (5 sin(B)/cos(B)) / (2 - 3 sin²(B)/cos²(B))

Multiplying uniformly by cos²(B) gives

tan(A + B) = 5 sin(B) cos(B) / (2 cos²(B) - 3 sin²(B))

Recall the double angle identities for sin and cos:

sin(2x) = 2 sin(x) cos(x)

cos(2x) = cos²(x) - sin²(x)

and multiplying uniformly by 2, we find that

tan(A + B) = 10 sin(B) cos(B) / (4 cos²(B) - 6 sin²(B))

… = 10 sin(B) cos(B) / (4 (cos²(B) - sin²(B)) - 2 sin²(B))

… = 5 sin(2B) / (4 cos(2B) - 2 sin²(B))

The Pythagorean identity,

cos²(x) + sin²(x) = 1

lets us rewrite the double angle identity for cos as

cos(2x) = 1 - 2 sin²(x)

so it follows that

tan(A + B) = 5 sin(2B) / (4 cos(2B) + 1 - 2 sin²(B) - 1)

… = 5 sin(2B) / (4 cos(2B) + cos(2B) - 1)

… = 5 sin(2B) / (4 cos(2B) - 1)

as required.

5 0

2 years ago

The time spent to travel a certain distance varies inversely as a car's speed. If it takes 5½ hours to travel a certain distance

Licemer1 [7]

Answer:

6.6h

Step-by-step explanation:

So it takes 5.5 hours going at a speed of 60 miles per hour, multiply these two and we get a distance of 330 miles
Use this distance to find the time if speed is 50 miles per hour, so time is derived by dividing the distance by the speed
330 miles divide by 50 miles per hour gives 6.6 hours

5 0

3 years ago

Consider the quadratic function f(x) = x2 – 5x + 6.

PolarNik [594]

A = 2
b = -5
c = 6

The coefficients are 2 and -5
The constant is 6

5 0

3 years ago

Complete the tables of values.

Vladimir [108]

Answer:

$a=1\\b=\frac{1}{16}\\\\c=\frac{1}{256}\\\\d=1\\e=\frac{4}{9}\\\\f=\frac{16}{81}$