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3 years ago

X^3-6x^2-7x+60=0 i need help

Mathematics

1 answer:

alexgriva [62]3 years ago

6 0

Answer:

x= -3, 4 or 5

Step-by-step explanation:

if you factor out the expressions, they look like this:

(x+3)(x-4)(x-5) = 0

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How can you use properties of operation to solve problems?

MAXImum [283]

First of all not to be rude, but it is order of operations not properties of operations. Second, you can solve equations by going in the order of PEMDAS or Parentheses, Exponents, Multiplication, division, addition, and subtraction. Multiplication and division are switchable, addition and subtraction. If you do not follow this order you get the equation or inequality wrong.

7 0

3 years ago

F(x) = x2 – x-1<br> What is the average rate of change of f over the interval -1 < x < 1?

Leni [432]

Answer:

-2 < x - 1 < 0

Step-by-step explanation:

2x - × - 1 = x -1

-1 < x < 1

2. -2 < x - 1 < 0

7 0

4 years ago

Read 2 more answers

Porky the pig weighs 1,125 lbs. Less than Kobe the Cow. After each gains 50lbs. Kobe the Cow will weigh ten times as much as por

Papessa [141]

Answer:

Step-by-step explanation:

Let x represent the initial weight of Porky the pig.

Porky the pig weighs 1,125 lbs less than Kobe the Cow. This means that the initial weight of Kobe the cow is

x + 1125

After each gains 50lbs. Kobe the Cow will weigh ten times as much as porky the pig. This means that

(x + 1125) + 50 = 10(x + 50)

x + 1125 + 50 = 10x + 500

10x - x = 1125 + 50 - 500

9x = 675

x = 675/9

x = 75

Porky's current weight is

75 + 50 = 125 lbs

Kobe's current weight is

(75 + 1125) + 50

= 1250 lbs

4 0

3 years ago

You take a quiz with 6 multiple choice questions. After you studied your estimated that you would have about an 80 % chance of g

Arada [10]

Answer:

1.15%

Step-by-step explanation:

To get the probability of m independent events you multiply the individual probability of each event. In this case we have m independent events, each one with the same probability, therefore:

$p^{m}$

$0.8^{20} = 1.15\%$

This is a particlar scenario of binomial distribution problem. So the binomial distribution questions are about the number of success of m independent events, where every individual event has the same p probability. In the question we have 20 events and each event has a probability of 80%. The binomial distribution formula is:

$\binom{n}{k} * p^{k} * (1-p)^{n-k}$

n is the number of events

k is the number of success

p is the probability of each individual event

$\binom{n}{k}$ is the binomial coefficient

the binomial coefficient allows to find the subsets of k elements in a set of n elements. In this case there is only one subset possible since the only way to get 20 of 20 correct questions is to getting right all questions (for getting 19 of 20 questions there are many ways, for example getting the first question wrong and all the other questions right, or getting second questions wrong and all the other questions right, etc).

$\binom{n}{k} = \frac{n!}{k!(n-k)!}$

therefore, for this questions we have:

$\frac{20!}{20!(20-20)!} * 0.8^{20} * (1-0.8)^{0} = 1.15\%$

4 0

3 years ago

Can somebody help please??? Explain... I need help with with this one problem:

LUCKY_DIMON [66]

Well - I mean. If every lunch costs $4 that means that the relationship should be linear.

You used to be able to draw graphs. But plot it out.

3 0

4 years ago