Answer:
The correct option is;
Use a scale factor of 2
Step-by-step explanation:
The parameters given are;
A = (1, -6)
B = (5, -6)
C = (6, -2)
D = (0, -2)
A'' = (1.5, 4)
B'' = (3.5, 4)
C'' = (4, 2)
D'' = ( 1, 2)
We note that the length of side AB in polygon ABCD = √((5 -1)² + (-6 - (-6))²) = 4
The length of side A''B'' in polygon A''B''C''D'' = √((3.5 -1.5)² + (4 - 4)²) = 2
Which gives;
AB/A''B'' = 4/2 = 2
Similarly;
The length of side BC in polygon ABCD = √((6 -5)² + (-2 - (-6))²) = √17
The length of side B''C'' in polygon A''B''C''D'' = √((4 -3.5)² + (2 - 4)²) = (√17)/2
Also we have;
The length of side CD in polygon ABCD = √((6 -0)² + (-2 - (-2))²) = 6
The length of side C''D'' in polygon A''B''C''D'' = √((4 -1)² + (2 - 2)²) = 3
For the side DA and D''A'', we have;
The length of side DA in polygon ABCD = √((1 -0)² + (-6 - (-2))²) = √17
The length of side D''A'' in polygon A''B''C''D'' = √((1.5 -1)² + (4 - 2)²) = (√17)/2
Therefore the Polygon A B C D can be obtained from polygon A''B''C''D'' by multiplying each side of polygon A''B''C''D'' by 2
The correct option is therefore;
Use a scale factor of 2.
Answer: 1/6 is not equal to 6/12 because 6/12 is 1/2 and 1/6 is less
Step-by-step explanation:
We have expression 
that renders the system of inequalities,
Which can be simplified to,
So what we get is something greater than -1 and at the same time greater or equal to 5, so the solution is,
![x\in(\infty,-1)\cap(\infty, 5]=\boxed{(\infty,5]}](https://tex.z-dn.net/?f=x%5Cin%28%5Cinfty%2C-1%29%5Ccap%28%5Cinfty%2C%205%5D%3D%5Cboxed%7B%28%5Cinfty%2C5%5D%7D)
.
Hope this helps.
Answer:
z=3 because in the 2(z+3) is like (z+2)+(z+6)
