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zlopas [31]
3 years ago
9

If the clothing maker bought 500 m2 of this fabric, how much money did he lose? Use 1tepiz=0.625dollar and 0.9144m=1yard.

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

He lost $ 53,239 for the 500 m² of clothes he paid

<h3><em>Further explanation </em></h3>

7 main quantities have been determined based on international standards, namely:

  • 1. Length, meters (m)
  • 2. Time, second (s)
  • 3. Mass, kilograms (kg)
  • 4. Temperature, kelvin (K)
  • 5. Light intensity, candela (cd)
  • 6. Electric current, ampere (A)
  • 7. Amount of substance, mol (m)

The derivative magnitude is the quantity of principal quantities. So in addition to 7 principal quantities, other quantities are derived quantities

Yard is a unit of length commonly used by Commonwealth countries

The agreed conversion is

0.9144 m = 1 yard or 1 m = 1.0933 yards

So that 1 m² = 1,196 yards²

In the problem, there are 500 m² paid so the conversion is = 598 yards2²

To find out how many dollars the loss is, then we have to compare local prices (in this case prices in New York) with prices at small islands

1. We see prices in New York:

The price of this cloth in New York is 120 dollars / yard, so for 598 yards² the pay is:

$ 120 / yard² x 598 yards² = $ 71,760

2. We see prices at a small island

1 tepiz = $ 0.625

the clothing maker accepts 400 tepizes / m² so the number of dollars becomes:

400 tepizes / m² x $ 0.625 = $ 250 / m² = $ 209.03 / yard²

so that for the 598 yards paid:

$ 209.03 / yard² x 598 yard² = $ 124,999.94

We see that the price paid in the small island is more than the price in New York with a difference:

$ 124,999.94 - $ 71,760 = $ 53,239

<h3><em>Learn more </em></h3>

A vineyard has 145 acres of Chardonnay grapes

brainly.com/question/982615

the mass of a gold bar that is 7,379 × 10-4 m3 in volume

brainly.com/question/4773300

the quantity of 0.0075 meters expressed in centimeters

brainly.com/question/2867118

Keywords: Yard, cloth, dollars

Ivanshal [37]3 years ago
7 0
1 yard^2 = 0.8361m^2.? 

<span>The solution to the problem is as follows:

So he spent (.625 x 400) = $250.00 per m^2. </span>
He paid out (500 x 250) = $125,000 on the deal. 
He received (500 / 0.8361) = 598.014592 yard^2 of fabric. 
That would have cost (598.014592 x 120) = $71,761.75 locally. 
He lost (125,000 - 71,761.75) = $53,238.25 on the deal. 

<span>You can rework with the incorrect conversion factor.

I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
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For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200?
Morgarella [4.7K]

Answer:

48

Step-by-step explanation:

We are asked that the value of (4n + 7) will be an integer > 1 and < 200, for how many integer values of n.

So, equating (4n + 7) with 200 we can get the value.

4n + 7 = 200

⇒ 4n = 193

⇒ n = 48.25

Hence, the value of n will be the largest integer less than 48.25.

Therefore, the number of integer values of n will be 48. (Answer)

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3 years ago
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5 0
3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this question, we have that:

\pi = 0.21

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.645\sqrt{0.21*0.79}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.21*0.79}}{0.03})^2

n = 498.81

Rounding up

A sample of 499 is needed.

8 0
3 years ago
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