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3 years ago

Solve 3- x/2<=18 pls help

Mathematics

1 answer:

antoniya [11.8K]3 years ago

6 0

Answer:

IDK

Step-by-step explanation:

but you should ask M a t h w a y it is a great math solving thing.

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In △ABC, point P∈AC with AP:PC=1:3, point Q∈AB so that AQ:QB=3:4, Find the ratios A(PBQ) : A(PBC) and A(AQP) : A(ABC)

ludmilkaskok [199]

Answer:

The ratio APBQ : APBC is 4:21, AAQP : AABC is 3:28

Step-by-step explanation:

Data provided in the question

AP : PC = 1 : 3

So let us assume AP = x and PC = 3x.

And, If AQ : QB = 3 : 4

So, let us assume AQ = 3y and QB = 4y.

Now we have to find the area of ΔAQP and ΔABC

$A_{AQP}=\dfrac{1}{2}\cdot AP\cdot AQ\cdot \sin\angle A=\dfrac{1}{2}\cdot x\cdot 3y\cdot \sin\angle A;$

$A_{ABC}=\dfrac{1}{2}\cdot AC\cdot AB\cdot \sin\angle A=\dfrac{1}{2}\cdot (x+3x)\cdot (3y+4y)\cdot \sin\angle A=\dfrac{1}{2}\cdot 4x\cdot 7y\cdot \sin\angleA$

Therefore

$\dfrac{A_{APQ}}{A_{ABC}}=\dfrac{\frac{1}{2}\cdot x\cdot 3y\cdot \sin\angle A}{\frac{1}{2}\cdot 4x\cdot 7y\cdot \sin\angleA}=\dfrac{3}{28}.$

Now

$\dfrac{A_{APQ}}{A_{ABP}}=\dfrac{\frac{1}{2}\cdot x\cdot 3y\cdot \sin\angle A}{\frac{1}{2}\cdot x\cdot (3y+4y)\cdot \sin\angle A}=\dfrac{3}{7}.$

Now after solving these two ratios we can find

$A_{ABP}=\dfrac{7}{3}A_{APQ}\Rightarrow A_{PBQ}=A_{APB}-A_{APQ}=\dfrac{7}{3}A_{APQ}-A_{APQ}=\dfrac{4}{3}A_{APQ}$

$A_{ABC}=\dfrac{28}{3}A_{APQ}\Rightarrow A_{PBC}=A_{ABC}-A_{APB}=\dfrac{28}{3}A_{APQ}-\dfrac{7}{3}A_{APQ}=7A_{APQ}.$

Therefore

$\dfrac{A_{PBQ}}{A_{PBC}}=\dfrac{\frac{4}{3}A_{APQ}}{7A_{APQ}}=\dfrac{4}{21}.$

Hence, we applied the above equation so that we can get to know the ratios

3 0

4 years ago

use the numbers 1,3,4,6 exactly once with any basic math operation(multiplication,division,addition and subtraction) to total 24

drek231 [11]

Step-by-step explanation:

It is 4*6! We have to play with these numbers (1,3, and 4) to create 4, or we have to play with these numbers (1,3, and 6) to create 6.

If you divide 6 by 1/4, you will get 24.

If you divide 4 by 1/6, you will get 24.

How to create 1/4 from 1,3, and 4?

How to create 1/6 from 1,3, and 6?

Creating 1/4 from 1,3, and 4 is possible by doing this: 1–3/4, it is =1/4!

So, the answer is 6/[1–3/4]=24.

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3 years ago

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What’s equivalent to 5(2x+6)

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3 years ago

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The circle below is centered at the point (-3/4) and has a radius of length 3 what is its equation??

Agata [3.3K]

{x-(-3/4)}^2=3^2
(x+3/4)^2=9
{(4x+3)/4}^2=9
(4x+3)^2/16=9
(4x+3)^2=9*16
16x^2+2*4x*3+3^2=144
16x^2+24x+9=144
16x^2+24x+9-144=0
16x^2+24x-135=0

6 0

3 years ago

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F(x) = 3(3x + 4)<br> The inverse

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

find the inverse of the function y=9x+12

To find the inverse function, swap x and y, and solve the resulting equation for x.

If the initial function is not one-to-one, then there will be more than one inverse.

So, swap the variables: y=9x+12 becomes x=9y+12.

Now, solve the equation x=9y+12 for y.

$f^{-1}$ (x) = (x-12)/9

y=(x−12)/9

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3 years ago