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const2013 [10]
3 years ago
5

use the numbers 1,3,4,6 exactly once with any basic math operation(multiplication,division,addition and subtraction) to total 24

​
Mathematics
2 answers:
allochka39001 [22]3 years ago
8 0
Among the given numbers you can see that 6*4 gives you 24 but you have to use 1 and 3 .

You can't multiply 1 and 3 in numerator because you won't get 24, and you can't even divide it by 1,3 .

So only way is to get 1 in the denominator which can be obtained by

6/(1–(3/4)

which simplifies to 6/(1/4) = 24
drek231 [11]3 years ago
3 0

Step-by-step explanation:

It is 4*6! We have to play with these numbers (1,3, and 4) to create 4, or we have to play with these numbers (1,3, and 6) to create 6.

If you divide 6 by 1/4, you will get 24.

If you divide 4 by 1/6, you will get 24.

How to create 1/4 from 1,3, and 4?

How to create 1/6 from 1,3, and 6?

Creating 1/4 from 1,3, and 4 is possible by doing this: 1–3/4, it is =1/4!

So, the answer is 6/[1–3/4]=24.

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Use the information in the figure. If F=116, find E<br><br> 58<br> 32<br> 116<br> 64
My name is Ann [436]

Step-by-step explanation:

Given that,

  • m∠F = 116°

We have to find the value of m∠E.

Here, two sides are equal, thus it is an isosceles triangle. As the two sides are equal, so their angles must be equal. So, ∠E and ∠D will be equal. Let us assume the measures of both ∠E and ∠D as x.

→ Sum of all the interior angles of ∆ = 180°

→ ∠E + ∠D + ∠F = 180°

→ 116° + x + x = 180°

→ 2x = 180° – 116°

→ 2x = 64°

→ x = 64° ÷ 2

→<u> x = 32°</u>

Henceforth,

→ m∠E = x

→ m∠E = 32°

\\

~

6 0
3 years ago
Suppose the average math SAT score for students enrolled at local community college is 490.4 with a standard deviation of 63.7.
lakkis [162]

Answer:

Option B) 9.1      

Step-by-step explanation:

We are given the following in the question:

Average score = 490.4

Standard deviation = 63.7

Sample size, n = 49

Formula:

=\dfrac{\sigma}{\sqrt{n}}

Putting values, we get,

Standard error =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{63.7}{\sqrt{49}} = 9.1

Thus, the correct answer is

Option B) 9.1

8 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
1. If the product of the integers a,b, and c is 1, then what is the difference between the largest and the smallest possible val
Natali5045456 [20]
For question 1, the largest value would be 1 and the smallest value would be -1. A, B, and C are either all 1 or two is negative and one is positive, either way the number is 1 and it's opposite. 1^2 is 1, 1^3 is 1, 1^4 is 1. The product is 1. -1^2 is -1, -1^3 is -1, -1^4 is -1. The product is -1. Now the difference. 1 - (-1), which is 1 + 1, the answer is [D) 2]
4 0
3 years ago
Find the volume of a right circular cone that has a height of 2.5 m and a base with a diameter of 18.6 m. Round your answer to t
dem82 [27]

Answer:

226.4 m³.

Step-by-step explanation:

The volume of a right cone with a circular base is:

\displaystyle V = \frac{1}{3} \pi\cdot r^{2}\cdot h,

where

  • V is the volume of the cone,
  • r is the radius of the cone,
  • and h is the height of the cone.

The radius of the circular base is one-half its diameter.

\displaystyle r= \frac{1}{2}h=9.3\;\text{m}.

\displaystyle V = \frac{1}{3} \pi\cdot r^{2}\cdot h = \frac{1}{3} \pi \times 9.3^{2} \times 2.5 \approx 226.4\;\text{m}^{3}.

5 0
3 years ago
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