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Valentin [98]
2 years ago
13

What is the distance between 5,4 and -1,1

Mathematics
1 answer:
spayn [35]2 years ago
8 0

Answer:

3\sqrt{5}

Step-by-step explanation:

Calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (5, 4) and (x₂, y₂ ) = (- 1, 1)

d = \sqrt{(-1-5)^2+(1-4)^2}

   = \sqrt{(-6)^2+(-3)^2}

   = \sqrt{36+9}

   = \sqrt{45}

   = 3\sqrt{5} ← exact value

   ≈ 6.71 ( to 2 dec. places )

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15x {y}^{7} z

Step-by-step explanation:

<h3>Factorize the Expressions</h3>

15x {y}^{2} z = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z

30 {x}^{2}  {y}^{7} z = 2 \times 3 \times 5 \times x \times x \times y \times y \times y \times y \times y \times y \times y \times z

<h3>Factor out the Common Factors</h3>

gcf = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z

<h3>Multiply the Common Factors</h3>

3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z = 15x {y}^{7} z

The Factored expressions are

15x {y}^{7} z

And

15x {y}^{7} (2x)

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