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aleksley [76]
3 years ago
6

Determine whether the following question is a statistical question. If it is a statistical question, identify the units for the

answer.
An antique collector wants to know the age of a particular chair in a shop.
A This is a statistical question, and the units are years.
B This is not a statistical question.
Mathematics
1 answer:
Mkey [24]3 years ago
8 0

Answer:

This is not a statistical question.

Step-by-step explanation:

A statistical question is one that can be answered by collecting data and where there will be variability, or more than one answer, in that data.

Since the age of a chair can only be one number,  the question is not statistical.

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Hi. Could you please help me with this question??
Liula [17]
B) 23
Add what you know together, 6 + 2 + 2 + 2 + 3.5. Fill in what you don’t by looking at other sides. 3.5 + 2 + 2.
5 0
3 years ago
Use the distributive property to simplify -8(5x-3)
Alexxandr [17]

Answer:

-40x+24

Step-by-step explanation:

Use distributive property.

-8(5x-3)\\\rightarrow -8 * 5x = -40x\\\rightarrow -8*-3= 24\\\\\text {So: }-8(5x-3) \rightarrow -40x+24

6 0
4 years ago
Read 2 more answers
Use the distributive property to remove the parenthesis<br><br> 2=(v-8)
Tpy6a [65]

Answer:

v = 10

Step-by-step explanation:

2 = v - 8

add 8 to both sides

10 = v

8 0
3 years ago
Differentiate Vx(x + 2) with respect to x.
Travka [436]

Answer:

y'= \frac{3x+2}{2\sqrt{x} }

General Formulas and Concepts:

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

y=\sqrt{x} (x+2)

<u>Step 2: Rewrite</u>

y=x^{\frac{1}{2} } (x+2)

<u>Step 3: Differentiate</u>

  1. Product Rule [Basic Power/Chain Rule]:                 y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)
  2. Simplify:                                                                            y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}
  3. Rewrite:                                                                                        y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}
  4. Add:                                                                                                       y'= \frac{3x+2}{2\sqrt{x} }
7 0
3 years ago
The graph of f(x) = is shown with g(x). Which equation represents the graph of g(x)? g(x) = g(x) = g(x) = + 1 g(x) = –1
tresset_1 [31]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
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