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zhenek [66]
3 years ago
6

QUICKKKKKKKK EXPERTS/ACE/TRUSTED HELPERS

Mathematics
1 answer:
Anika [276]3 years ago
7 0
Function 2 has greater rate of change and greater y intercept than function 1
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suppose 7,500 is invested at 1.5%, compounded continuously. what will the account balance be in 16 years?​
viktelen [127]

Answer:

\boxed {\boxed {\sf \$9,534.37}}

Step-by-step explanation:

The formula for continuously compounded is:

A=Pe^{rt}

where P is the principal amount, r is the interest rate as a decimal, and t is the amount of time.

The principal amount is $7,500 and time is 16 years. The interest rate is 1.5%. Convert this to a decimal- divide by 100 or move the decimal places two spots to the left.

  • 1.5/100= 0.015         or           1.5 --> 0.15 --> 0.015

Now we know all the values and can substitute them into the formula.

P= 7500 \\r= 0.015 \\t= 16

A= 7500(e^{0.015*16})

Solve the multiplication in the exponent first.

A= 7500(e^{24})

Solve the exponent.

A= 7500 (1.27124915)

A=9534.368627

Round to the nearest cent (hundredth place). The 8 in the thousandth place tells us to the round the 6 to a 7.

A=9534.37

The account balance will be <u>$9,534.37</u> after 16 years.

7 0
3 years ago
Need help supper fast pls
DIA [1.3K]
I feel bad for you science is hard u know that
6 0
4 years ago
Alana's employer purchased a health insurance plan that costs $565 per month and requires that Alana pays $125 toward the plan.
aliina [53]
If Alana pays $125/mo toward an insurance plan that costs $565/mo then her employer must be paying the difference = 565-125 = 440/mo.For the full year of 12 months then her employer pays = 12*440 = $5280.
6 0
3 years ago
What is 3*ln(5)? Expanded and get the exact answer.
Mrac [35]

Answer:

  ln(125) ≈ 4.828314

Step-by-step explanation:

The relevant log relation is ...

  log(a^b) = b·log(a)

__

This means your expression is equivalent to ...

  3·ln(5) = ln(5^3) = ln(125) ≈ 4.828314

__

The "exact" answer is ln(125).

5 0
3 years ago
How can i solve this<br> f:d-&gt;R<br> f(x)=x at power2/x-1
Leto [7]
X - 1 is not null => x is not 1 => D = R - {1};
4 0
3 years ago
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