Answer:
The midpoint of the segment is (-0.5,0.5).
Step-by-step explanation:
Midpoint of a segment:
The midpoint of a segment is given by the mean of its coordinates.
Segment with end points (4,2),(-5,-1)
x-coordinates: 4 and -5
y-coordinates: 2 and -1
x-coordinate of the midpoint:

y-coordinate of the midpoint:

The midpoint of the segment is (-0.5,0.5).
The answer is 3ax -by + c hope this helps
Answer:

Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner
is:

where :
(a and b are the length and the breath of the rectangle respectively )


![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)

Thus; the moment of inertia of the lamina about one corner is 
You can work it out by using trial and error
so you get
x=3 , y=2
Answer:
242 2/3in^3
Step-by-step explanation:
The formula is l*w*h. So if you multiply all of them you'll get 242 2/3.