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luda_lava [24]
2 years ago
7

Find the nth term of 6,8,10,12

Mathematics
1 answer:
klemol [59]2 years ago
4 0

Answer:

6 8 10 12 14 16 18 20 22

1 2. 3. 4. 5. 6. 7. 8. 9

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She improved about 4.3 words per min each week
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A musical group is putting on show at the theatre. They collected $880 from 120 people attending. The price of an adult ticket i
pantera1 [17]

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Step-by-step explanation:

7 0
3 years ago
3 years ago a father was 3 times as old as his son, in five years time he will be twice as old as his son, what will be the sum
ivolga24 [154]

Answer: 46 years

Step-by-step explanation:

Let the father's age be x and the son's age be y, then 3 years ago:

Father = x - 3

son     = y - 3

Then , from the first statement :

x - 3 = 3 ( y - 3 )

x - 3 = 3y - 9

x     = 3y - 9 + 3

x     = 3y - 6 .......................................... equation 1

In five years time

father = x + 5

son = y + 5

Then , from the second statement

x + 5 = 2 ( y + 5 )

x + 5 = 2y + 10

x       = 2y + 10 - 5

x       = 2y + 5 ........................ equation 2

Equating equation 1 and 2 , we have

3y -6 = 2y + 5

add 6 to both sides

3y = 2y + 5 + 6

subtract 2y from both sides

3y - 2y = 11

y = 11

substitute y = 11 into equation 1 to find the value of x

x = 3y - 6

x = 3(11) - 6

x = 33 - 6

x = 27

This means that the father is presently 27 years and the son is presently 11 years.

In four years time

father = 27 + 4 = 31

son = 11 + 4      = 15

sum of their ages in four years time will be

31 + 15 = 46 years

5 0
3 years ago
Read 2 more answers
**PLEASE HELP**
Sav [38]
Your answer would be "D", because when finding the GCF of a term, you want to take the most out of it. Following the procedure of D, finding the greatest shared factor of 10 and 15 and the greatest shared power between exponent 2 and exponent 3, would allow you to find the GCF.
8 0
3 years ago
Given logx 2=p and logx 7=q , express log7 4x² in terms of p and q​
kodGreya [7K]

Answer:

[2(p + 1)]/q

Step-by-step explanation:

logx 2 = p

logx 7 = q

log7 4x² = log7 (2x)²

= (logx (2x)²)/(logx 7)

= (2 logx 2x)/(logx 7)

= (2 logx 2 + 2 logx x)/(logx 7)

= (2p + 2)/q

= [2(p + 1)]/q

5 0
2 years ago
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