No, a cubic equation can not have three complex roots. This is because it turns twice and one end goes to positive infinity and one end goes to negative infinity. Thus, one of these MUST cross the x-axis at some point, meaning y = 0 and a real root exists.
Yes, a cubic equation can have three real roots if it cuts the x-axis three times.
Hanna bought 85 candies and ate 20 of them. How many candies are left?
X - an amount

To increase an amount by 3% you can multiply the amount by 1.03.
Circumference of Circle=C, =2(pi)(radius)
Radius of Circle=r
Side of square=x
f(x)=area of circle
g(r)=area of square
16 feet=C+4x
C=16-4x
2(pi)(r)=16-4x
2(pi)(r)=2(8-2x)
(pi)(r)=8-2x
r=(8-2x)/(pi)
x=(8-(pi)r)/2
f(x)=(pi)(r^2)
f(x)=(pi)((8-2x)/(pi))^2
f(x)=((8-2x)^2)/(pi)
f(x)=((64-32x+4x^2))/(pi)
g(r)=((8-(pi)r)/2)^2
g(r)=((64-16(pi)r+(pi)^2(r^2))/4
Answer:

is the fraction of sensors upgraded per unit.
Step-by-step explanation:
We are given the following in the question:
Let x be the number of upgraded sensors in one unit and y be the number of non-upgraded sensors in one unit.
Number of modular units = 30
Since some part of unit is upgraded and some are non-upgraded, then, we can write the equation:

Number of non-upgraded sensors =

Thus, we can write the equation:

Fraction of sensors upgraded per unit =
