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3 years ago

Please help me asap thank you!

Mathematics

1 answer:

vlabodo [156]3 years ago

8 0

Answer:

25a-20

Step-by-step explanation:

15a+10a-20=

25a-20

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A circle centered at the origin has a radius of 10 units. The terminal side of an angle, Theta, intercepts the circle in Quadran

Tanzania [10]

Since the circle is centered at the origin, we can use the equations
x² + y² = r²
x = r cos θ
y = r sin θ

We know y = 8 and r = 10. Solving for x
x² + 8² = 10²
x = 6

From this equation:
x = r cos θ
6 = 10 cos θ
cos θ = 6/10 = 0.6

7 0

3 years ago

The 12th term and the sim of 1+3+5+7+.....

zzz [600]

To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.

subtract 1 from 3

3-1=2

So each number is having 2 added to it.

Now add two to 7 and the numbers afterwards till you get the 12th term

7+2=9

1+3+5+7+9

9+2=11

1+3+5+7+9+11

11+2=13

1+3+5+7+9+11+13

13+2=15

1+3+5+7+9+11+13+15

15+2=17

1+3+5+7+9+11+13+15+17

17+2=19

1+3+5+7+9+11+13+15+17+19

19+2=21

1+3+5+7+9+11+13+15+17+19+21

21+2=23

1+3+5+7+9+11+13+15+17+19+21+23

So 23 is the 12th term

7 0

4 years ago

What is <2 if <4 is 35

Rudiy27

Answer:

2 is 17.5

Step-by-step explanation:

bc the half of 4 is 2 since 4 is 35 we have to find the half of 35 and how we do that is by dividing it by 2.

35%2=17.5 so 2 is equal 17.5 so <2 is 17.5

4 0

3 years ago

Simplify (square root 2)( square root of 2^3)

steposvetlana [31]

Answer:

$\large\boxed{(\sqrt2)(\sqrt{2^3})=4}$

Step-by-step explanation:

$(\sqrt2)(\sqrt{2^3})\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{2\cdot2^3}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{2^{1+3}}=\sqrt{2^4}\\\\(1)=\sqrt{2^{2\cdot2}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(2^2)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2^2=4\\\\(2)=\sqrt{2\cdot2\cdot2\cdot2}=\sqrt{16}=6\ \text{because}\ 4^2=16$

8 0

3 years ago

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 18/fts . The ball's height h (in feet) afte

inna [77]

Hello! First insert 6 where the h is located. So we have an equation that looks like the following. $6 = 2 - 18t + 16t^2$

Although you could leave the equation in its original form, I am going to switch it around.
$6 = 2 - 18t + 16t^2$
$16t^2 - 18t + 2 = 6$
Move the 6 to the other side and do the math
$16t^2 - 18t + 2 - 6 = 6 - 6$
$16t^2 - 18t -4 = 0$
Factor and after factoring your T will be as follows
t = $\frac{9}{16} - \frac{\sqrt{145}}{16}$ = -0.1900
t = $\frac{9}{16} + \frac{\sqrt{145}}{16}$ = 1.315

4 0

3 years ago