Rezolvati 1) -2x+1= -7 2) 6+3x= -54+x 3) 2x+9= 7 +x 4) 3-2x= -x -6 5) -3(x+1) = -6 6) -4 (x -2)=12 7) -7(x-3)= -14
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Kory and Leanne will meet each other again after 36 minutes from starting i.e. at 10:36 am .
<u>Step-by-step explanation:</u>
Here we have , Leanne runs a lap in 12 minutes. Kory runs a lap in 9 minutes. We need to find out that If they both start running at 10 am, at what time will they both cross the start together again . Let's find out:
Kory runs a lap in 9 minutes and , Leanne in 12 minutes , in order to find at what time will they both cross the start together again we will find LCM of 9 & 12 :
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So ,LCM of 9 & 12 is 36 .That means Kory and Leanne will meet each other again after 36 minutes from starting i.e. at 10:36 am .
In clear way , Kory will run race as :
1st lap = 9 minutes
2nd lap = 18 minutes
3rd lap = 27 minutes
4th lap = 36 minutes , i.e. at 10:36 am he'll complete his 4th lap
For , Leanne
1st lap = 12 minutes
2nd lap = 24 minutes
3rd lap = 36 minutes i.e. at 10:36 am he'll complete his 3rd lap .
This means Kory & Leanne will meet at 10:36 am completing there 4th and 3rd lap respectively .