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svet-max [94.6K]
3 years ago
7

You received 1⁄4 pound of candy from your grandmother, 1⁄2 pound of candy from your sister, and 1⁄8 pound of candy from your bes

t friend. How many pounds of candy did you receive?
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
5 0
Total pounds of candy you received = Pounds of candy received from Grandmother + Pounds of candy received from Sister + Pounds of Candy received from Best Friend

Add them all up to find the total you received.

Total pounds of candy you received = 1/4 + 1/2 + 1/8
= 2/8 + 4/8 + 1/8 = 7/8 Pounds

When changing the denominator of a fraction, always make sure to change the numerator proportionately as well. For 1/4, since you wish to change the denominator to 8 (which is the largest denominator in the group), and since 8 is equal to 4 × 2, the numerator will also have to be multiplied by 2 (I.e. 1 × 2). This will give you 2/8.

Hope this helps! :)
You might be interested in
To find 40% of 75 and calculate 2 of 5 . 75 . Does her calculation Correct value for 40% of 75
pickupchik [31]

Answer:

Yes, her calculation is correct. The value of 40% of 75 is 30.

Step-by-step explanation:

The value of 40% of 75 is

\frac{40}{100}\times 75=\frac{3000}{100}=30

The value of \frac{2}{5} of 75 is

\frac{2}{5}\times 75=2\times 15=30

From the above calculation it is noticed that the value of 40% of 75 and \frac{2}{5} of 75 are same, therefore the calculation is correct and the  value of 40% of 75 is 30.

4 0
3 years ago
Read 2 more answers
This is a System Of Equations and I'd like it to get solved by the Elimination or Substitution Method.x+2y=83x+5y=8
Sonbull [250]

Answer:

x=133 y=-25

Step-by-step explanation:

I'll do both ways for you. So let's start with Substitution:

With the sub method, you have to set both equations equal to each other by setting them equal to the same variable. Since there is no coefficient in front of both x's in both equations, that variable will be easiest to solve for.

x + 2y = 83    &    x + 5y = 8

Solve for x.

x = 83 - 2y     &    x = 8 - 5y

Once you have solved for x, set each equation equal to one another and solve for y now.

83 - 2y = 8 - 5y

Isolate all variables to one side:

83 = 8 - 3y

Now subtract the 8 to fully isolate the y variable:

75 = -3y

Divide by -3:

-25 = y   Now that you have your first variable, plug it into one of the original equations and solve for x.

x + 2(-25) = 83

x - 50 = 83

x = 133

Now for the Elimination method. For this method you need to get rid of a variable by either subtracting/adding each equation together. Again, since you can subtract and x from both equations, you will be left with only the y variable to solve:

Put each equation on top of one another and subtract:

  x + 2y = 83

- (x + 5y = 8)

The x's will cancel out:

(x - x) + (2y - 5y) = (83 - 8)

Simplify:

-3y = 75

Solve for y

y = -25

Then, plug y = -25 into one of the original equations:

x + 5(-25) = 8

Solve for x:

x - 125 = 8

x = 133

Hope this helps!

8 0
2 years ago
A rock thrown vertically upward from the surface of the moon at a velocity of 36​m/sec reaches a height of s = 36t - 0.8 t^2 met
Verdich [7]

Answer:

a. The rock's velocity is v(t)=36-1.6t \:{(m/s)}  and the acceleration is a(t)=-1.6  \:{(m/s^2)}

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

  • Velocity is defined as the rate of change of position or the rate of displacement. v(t)=\frac{ds}{dt}
  • Acceleration is defined as the rate of change of velocity. a(t)=\frac{dv}{dt}

a.

The rock's velocity is the derivative of the height function s(t) = 36t - 0.8 t^2

v(t)=\frac{d}{dt}(36t - 0.8 t^2) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(36t\right)-\frac{d}{dt}\left(0.8t^2\right)\\\\v(t)=36-1.6t

The rock's acceleration is the derivative of the velocity function v(t)=36-1.6t

a(t)=\frac{d}{dt}(36-1.6t)\\\\a(t)=-1.6

b. The rock will reach its highest point when the velocity becomes zero.

v(t)=36-1.6t=0\\36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\\360-16t=0\\360-16t-360=0-360\\-16t=-360\\t=\frac{45}{2}=22.5

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

s(22.5) = 36(22.5) - 0.8 (22.5)^2\\s(22.5) =405

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = \frac{405}{2} =202.5 \:m

To find the time it reach half its maximum height, we need to solve

36t - 0.8 t^2=202.5\\36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\\360t-8t^2=2025\\360t-8t^2-2025=2025-2025\\-8t^2+360t-2025=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\\\\t=\frac{-360+\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2-\sqrt{2}\right)}{4}\approx 6.59\\\\t=\frac{-360-\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2+\sqrt{2}\right)}{4}\approx 38.41

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

36t - 0.8 t^2=0\\\\\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\\\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\\\t=0,\:t=45

The rock is aloft for 45 seconds.

5 0
3 years ago
A warehouse worker fills 150 orders per day on average. From day to day, the number of orders varies by 2%. What is the range of
choli [55]

Answer:

The range is from 147 to 153 orders per day

Step-by-step explanation:

orders varies by 2% means that orders can be LOWER THAN THE AVERAGE, or HIGHER THAN THE AVERAGE.

That is, by 2%.

First, we need to find the decimal of 2%, so

2/100 = 0.02

We multiply this with the average number of order, 150, to get the varying amount:

0.02 * 150 = 3

Thus, the range would be:

150 - 3 = 147

150 + 3 = 153

The range is from 147 to 153 orders per day

5 0
3 years ago
Do anybody play valorant?
BartSMP [9]

Answer:

i do, but i just started.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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