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svet-max [94.6K]
3 years ago
7

You received 1⁄4 pound of candy from your grandmother, 1⁄2 pound of candy from your sister, and 1⁄8 pound of candy from your bes

t friend. How many pounds of candy did you receive?
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
5 0
Total pounds of candy you received = Pounds of candy received from Grandmother + Pounds of candy received from Sister + Pounds of Candy received from Best Friend

Add them all up to find the total you received.

Total pounds of candy you received = 1/4 + 1/2 + 1/8
= 2/8 + 4/8 + 1/8 = 7/8 Pounds

When changing the denominator of a fraction, always make sure to change the numerator proportionately as well. For 1/4, since you wish to change the denominator to 8 (which is the largest denominator in the group), and since 8 is equal to 4 × 2, the numerator will also have to be multiplied by 2 (I.e. 1 × 2). This will give you 2/8.

Hope this helps! :)
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Student Debt – Vermont: The average student loan debt of a U.S. college student at the end of 4 years of college is estimated to
mezya [45]

Answer:

The confidence interval is (24116.3878,24883.6122).

Step-by-step explanation:

We are given the following information in the question:

Population mean, \mu = $23,500

Sample mean,\bar{x} = $24,500

Sample standard deviation,s = $2,800

Sample size, n =  146

Confidence interval:

\bar{x} \pm t_{critical}\frac{s}{\sqrt{n}}  

Putting the values, we get,

t_{critical}\text{ at}~\alpha_{0.05} = \pm 1.655436

24500 \pm 1.65543(\frac{2800}{\sqrt{146}} ) = 24500 \pm 383.6122 = (24116.3878,24883.6122)

The confidence interval is (24116.3878,24883.6122).

5 0
2 years ago
In triangle abc shown below side ab is 6 and side ac is 4
kaheart [24]

Question is Incomplete, Complete question is given below:

In Triangle ABC shown below, side AB is 6 and side AC is 4.

Which statement is needed to prove that segment DE is parallel to segment BC and half its length?

Answer

Segment AD is 3 and segment AE is 2.

Segment AD is 3 and segment AE is 4.

Segment AD is 12 and segment AE is 4.

Segment AD is 12 and segment AE is 8.

Answer:

Segment AD is 3 and segment AE is 2.

Step-by-step explanation:

Given:

side AB = 6

side AC = 4

Now we need to prove  that segment DE is parallel to segment BC and half its length.

Solution:

Now AD + DB = AB also AE + EC = AC

DB = AB - AD also EC = AC - AE

Now we take first option Segment AD is 3 and segment AE is 2.

Substituting we get;

DB = 6-3 = 3 also EC = 4-2 =2

From above we can say that;

AD = DB and EC = AE

So we can say that segment DE bisects Segment AB and AC equally.

Hence From Midpoint theorem which states that;

"The line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side."

Hence Proved.

7 0
3 years ago
This is algebra 1 math problem <br>f (×)=2/5x+10
Alina [70]
To find the inverse, interchange the variables and solve for y.

f^−1(x)=−25+5x/2
3 0
3 years ago
A number of cats got together and decided to kill between them 999919 mice. every cat killed an equal number of mice. Each cat k
vredina [299]

Answer:

Step-by-step explanation:10,000 cats

4 0
2 years ago
Read 2 more answers
How do I solve this using the system of equations?
Westkost [7]

Answer:

length: 16 m; width: 13 m

Step-by-step explanation:

Write each of the statements as an equation. You know that the formula for the perimeter is ...

P = 2(L +W)

so one of your equations is this one with the value of P filled in:

• 2L + 2W = 58

The other equation expresses the relation between L and W:

• L = W +3 . . . . . . . . the length is 3 meters greater than the width

There are many ways to solve such a system of equations. Since you have an expression for L, it is convenient to substitute that into the first equation to get ...

2(W+3) +2W = 58

4W +6 = 58 . . . . . . . simplify

4W = 52 . . . . . . . . . . subtract 6

W = 13 . . . . . . . . . . . .divide by 4

We can use the expression for L to find its value:

L = 13 +3 = 16

The length is 16 meters; the width is 13 meters.

6 0
3 years ago
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