On Monday, the high temperature in Abilene was 75.6 degrees Fahrenheit and the high temperature in New York City was 54 degrees
1 answer:
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Answer:
Step-by-step explanation:
The area of an isoceles triangle is:
A = base x height / 2
The base is the unequal side in the isosceles triangle. You have to calculate the height using the Pythagorean Theorem.
Since two side are equal in length, if you draw a vertical lined from where these two sides meet and bisect the base, you will create two right triangles.
So a² + b² = c² where c is the hypotenuse of the right triangle. This hypotenuse is also the two equal sides of the isosceles triangle. They told you the length of the base but you need to divide that in half since your line bisected the base.
So now you know one side of the right triangle is 8cm which is half of 16cm. You also know the hypotenuse is 17cm. Solve the Pythagorean Theorem for the other side and that will give you the height of your bisecting line.
8² + b² = 17² OR 64 + b² = 289
Solve for b
b² = 289 - 64 OR b² = 225 and finally b = which is 15
So now you can calculate the area of the triangle:
A = 16 x 15 / 2 or 240 / 2 which is 120
So the area is 120 cm²
Answer:
The first, second, and fifth statements are correct.
Step-by-step explanation:
We are given a circle with the equation:
And we want to select the statements that are true.
First, we can convert the equation into standard form. We can group each variable:
And complete the square for the first term:
Factor and simplify:
We can rewrite our equation as:
So, this tells us that we have a circle centered on (1, 0) with a radius of 3 units.
In this case, the first statement, second statement (the point (1,0) is on the x-axis), and fifth statements are correct (the square root of 9 is also 3).
Given:
Diameter of the hole = 30 cm
To find:
The area of the hole.
Solution:
The radius of a circle is always half of the diameter. It is given that the diameter of the hole is 30 cm. So, the radius of the hole is:
Area of a circle is:
Putting and
in the above formula, we get
Therefore, the area of the hold is 706.5 square cm.