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3 years ago

Write 6/9=a/b in simplest form

Mathematics

1 answer:

kobusy [5.1K]3 years ago

8 0

Answer:

2/3 = a/b

Step-by-step explanation:

6/9 = a/b

2/3 = a/b

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Factor the linear expression 24y - 40 using the greatest common factor of the terms

ANEK [815]

Factor: 24y-40
Answer: 8(3y-5)

Simplifying: 24y-40
Answer: There are no like terms.

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3 years ago

(JUSTIFY)The diameter of a wheel is 15 inches. How far would your hand move in one full turn of the wheel if you do not let go o

Elanso [62]

So,

The circumference of a circle is $2 \pi r, or \ \pi d, where \ d \ is \ the \ diameter.$

Substitute 15 for d
$15(3.14)$

47.1
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Your hand would move 47 inches.

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3 years ago

Multiply the decimals 12.5 multiply 1.4

LekaFEV [45]

Answer:

17.5

Step-by-step explanation:

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3 years ago

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3 years ago

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A rectangular parking lot has an area of 315 square yards. The width of the parking lot is 5 yards longer than the length of the

Blababa [14]

Answer:

Dimension of parking lot is approximately 15.425 × 20.425 yards.

Step-by-step explanation:

Given:

Area of the parking lot = $315 \ yd^2$

Let the length of the parking lot be $'l'$

Also Given:

The width of the parking lot is 5 yards longer than the length of the parking lot.

so we can say that;

width of the parking lot, $w=5+l$

We need to find the dimension of parking lot.

Solution:

Now we can say that;

Area of rectangle is equal to length times width.

framing in equation form we get;

$lw=315$

Now substituting the value of w in above equation we get;

$l(l+5)=315\\\\l^2+5l=315\\\\l^2+5l-315=0$

Now we will find the roots using quadratic equation.

$ax^2+bx+c =0$

a = 1

b=5

c=-315

Formula for quadratic equation is;

$l =\frac{-b\±\sqrt{b^2-4ac}}{2a}$

First we will find;

$\sqrt{b^2-4ac} = \sqrt{5^2-4\times1\times-315} =\sqrt{25+1260}=\sqrt{1285} \approx35.85$

Now we will substitute the value we get;

$l =\frac{-5\±35.85}{2\times1}= \frac{-5\±35.85}{2}$

Now we will find 2 roots we get;

$l= \frac{-5+35.85}{2}= \frac{30.85}{2}\approx15.425\\\\OR\\\\l =\frac{-5-35.85}{2}= \frac{-40.85}{2} \approx -20.425$

Now we get 2 values of length one is positive and other is negative.

But length of parking lot cannot be negative hence we will discard the negative value.

Hence the length of the parking lot = 15.425 yards

Width of the rectangular parking lot = $l+5=15.425+5 =20.425$

Hence we can say that dimension of parking lot is approximately 15.425 × 20.425 yards.

3 0

3 years ago