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3 years ago

Use the place-valué charro to quite a Numbers in the table that is 1/10 of given Number?

Mathematics

1 answer:

Lana71 [14]3 years ago

6 0

This is the answer for the Use the place-valué charro to quite a Numbers in the table that is 1/10 of given Number?

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17q^3 + 216q^3 algebra question

lukranit [14]

Answer:

233q^3

Step-by-step explanation:

You just have to plus both of them like 17+216 which is 233 because powers are same on both numbers and the variable would be simply copied.

6 0

3 years ago

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a random check of 150 southwest airlines flights last month identified that 113 of them arrived on time. what "on time" percent

qwelly [4]

113 / 150 = 0.753
0.753 x 100 = 75.3
75% on time

7 0

3 years ago

A biologist observed that a certain bacterial colony obeys the population growth law and that the colony triples every 4 hours.

MrRa [10]

Answer:

a) $P(t) = 2e^{0.275t}$

b) 54.225 square centimeters.

c) 2.52 hours

Step-by-step explanation:

The population growth law is:

$P(t) = P_{0}e^{rt}$

In which P(t) is the population after t hours, $P_{0}$ is the initial population and r is the growth rate, as a decimal.

In this problem, we have that:

The colony occupied 2 square centimeters initially, so $P_{0} = 2$

The colony triples every 4 hours. So

$P(4) = 3P_{0} = 6$

(a) An expression for the size P(t) of the colony at any time t.

We have to find the value of r. We can do this by using the P(4) equation.

$P(t) = P_{0}e^{rt}$

$6 = 2e^{4r}$

$e^{4r} = 3$

Applying ln to both sides, we get:

$4r = 1.1$

$r = 0.275$

$P(t) = 2e^{0.275t}$

(b) The area occupied by the colony after 12 hours.

$P(t) = 2e^{0.275t}$

$P(12) = 2e^{0.275*12}$

$P(12) = 54.225$

(c) The doubling time for the colony?

t when $P(t) = 2P_{0} = 2*2 = 4$ .

$P(t) = 2e^{0.275t}$

$4 = 2e^{0.275t}$

$e^{0.275t} = 2$

Applying ln to both sides

$0.275t = 0.6931$

$t = 2.52$

4 0

3 years ago

Zack took out a 30-year mortgage for $70,000 at 9%. How much is his monthly mortgage payment? please explanation.. I assume $630

BartSMP [9]

Answer:

$563.24

Step-by-step explanation:

The monthly payment on a mortgage loan is found using the amortization formula:

A = P(r/12)/(1 -(1 +r/12)^(-12t))

where A is the monthly payment on a loan of P at interest rate r for t years.

Filling in the given values, we find the payment to be ...

A = $70,000×(0.09/12)/(1 -(1 +0.09/12)^(-12·30)) ≈ $563.236

The monthly payment is about $563.24.

_____

<em>Additional comment</em>

Many graphing calculators and all spreadsheets have functions that will do this calculation for you.

8 0

2 years ago

Ax + c = R (solve for x)

sp2606 [1]

Ax + c = R (subtract c from each side)

Ax + c - c = R - c

Ax = R - c (divide A from each side)

Ax/A = (R-c)/A

x = $\frac{R-c}{A}$ <-answer

4 0

2 years ago

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