All categories

2 years ago

4 (k - 6) = 6 (-4 - 5k) a) 10 b) 0 c) -2 d) 8

Mathematics

1 answer:

user100 [1]2 years ago

3 0

Step-by-step explanation:

step 1. what is the question? solve for k? okay.

step 2. 4(k - 6) = 6(-4 - 5k)

step 3. 4k - 24 = -24 - 30k

step 4. 34k = 0

step 5. k = 0.

You might be interested in

Use the zero product property to find the solutions to the equation x2 – 15x – 100 = 0.

IrinaK [193]

Answer:

x= 20 x =-5

Step-by-step explanation:

x^2 – 15x – 100 = 0.

What two numbers multiply to -100 and add to -15

-20 * 5 = -100

-20 +5 = -15

(x-20) (x+5) =0

Using the zero product property

x-20 =0 x+5 = 0

x= 20 x =-5

7 0

3 years ago

Read 2 more answers

In which quadrant or on which axis each of the following points lie.

AlekseyPX

Answer:

(-3,5) Quad 2

(4,-1) Quad 4

(2,0) Positive X axis

(2,2) Quad 1

(-3,-6) Quad 3

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which of the equations below could be the equation of this parabola?

nirvana33 [79]

Answer:

$y=-4x^2$ is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

$y=-4x^2$

$\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

$\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}$

$\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)$

$\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)$

$\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}$

$y=-4x^2$

$\mathrm{The\:parabola\:params\:are:}$

$a=-4,\:m=0,\:n=0$

$x_v=\frac{m+n}{2}$

$x_v=\frac{0+0}{2}$

$x_v=0$

$\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}$

$y_v=-4\cdot \:0^2$

$y_v=0$

Therefore, the parabola vertex is

$\left(0,\:0\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}$

$a=-4$

$\mathrm{Maximum}\space\left(0,\:0\right)$

so,

$\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)$

Therefore, $y=-4x^2$ is the equation of this parabola. The graph is also attached.

7 0

3 years ago

In the library on a university campus, there is a sign in the elevator that indicates a limit of 16 persons. Furthermore, there

Vedmedyk [2.9K]

Answer:

a) 151lb.

b) 6.25 lb

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .