10 L of 30 % saline solution can be formed by mixing 4 L of 60 % saline solution and 6 L of 10 % saline solution.
Step-by-step explanation:
Let x be the number of liters of 60% saline solution
Now we require 10 L of 30% saline solution.
Liter soln % liters saline %
30 % 10 0.3
60 % x 0.6
10 % 10-x 0.1
Now forming the algebraic equation,
0.6x + 0.1 (10-x) = 10 (0.3)
0.6x + 1 - 0.1 x = 3
0.5 x = 2
x = 4 ( 4 l of 60 % solution is required. So 10 % saline solution required is 10 - 4 = 6 L).
Hence, 10 L of 30 % saline solution can be formed by mixing 4 L of 60 % saline solution and 6 L of 10 % saline solution.
Answer:
x = 3.25
y =4.75
Step-by-step explanation:
In order to Solve the following system of equations below algebraically using substitution method we say that;
let;
8x - 4y = 7
..................... equation 1
x + y = 8.......................... equation 2
from equation2
x + y = 8.......................... equation 2
x = 8 - y.............................. equation 3
substitute for x in equation 1
8x - 4y = 7
..................... equation 1
8(8-y) - 4y = 7
64-8y-4y=7
64-12y=7
collect the like terms
64-7 = 12y
57= 12y
divide both sides by the coefficient of y which is 12
57/12 = 12y/12
4.75 = y
y =4.75
put y = 4.75 in equation 3
x = 8 - y.............................. equation 3
x = 8 -4.75
x = 3.25
to check if your answer is correct, put the value of x and y in either equation 1 or 2
from equation 2
x + y = 8.......................... equation 2
3.25 + 4.75 =8
8=8.................... proved
Answer:
4
Step-by-step explanation:
3x2=6
6 times what gives 24?
6x4=24
So x=4
