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Ksenya-84 [330]
3 years ago
14

A square has vertices T(1,2), U(4,2), V(4,5), W(1,5). If the square is rotated clockwise 90 degrees around (0,0), what are the c

oordinates of W?

Mathematics
1 answer:
erastovalidia [21]3 years ago
6 0
<span>(5,-1) The key to this problem is ignoring all the information that you don't need. You really don't care about the coordinates for T, U, or V. Just W is all that matters. So make a graph, label the X and Y axis, and put a point at (1,5). Now simply turn the entire paper clockwise 90 degrees. If you do this, you'll see that what was the X axis is now the Y axis. And what was the Y axis is now the X axis. Label the axis again, and read the location of the point you marked. If you do so, you'll see that you have to go 5 spaces along the X axis, hence the 5. And you'll go 1 space down on the Y axis, hence the -1. So the coordinates of W(1,5) rotated 90 degrees clockwise around (0,0) changes to (5,-1).</span>
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Answer:

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The x-coordinate is the location of a point as measured along the x-axis. The y-coordinate is the location of a point as measured along the y-axis.

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Another way to describe the y-coordinate is that it <em>tells you how far to move from the origin parallel to the </em><em>y-axis</em>.

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zimovet [89]
70 / 35 = 2
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Fiesta28 [93]
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3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
3 years ago
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