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Ksenya-84 [330]
3 years ago
14

A square has vertices T(1,2), U(4,2), V(4,5), W(1,5). If the square is rotated clockwise 90 degrees around (0,0), what are the c

oordinates of W?

Mathematics
1 answer:
erastovalidia [21]3 years ago
6 0
<span>(5,-1) The key to this problem is ignoring all the information that you don't need. You really don't care about the coordinates for T, U, or V. Just W is all that matters. So make a graph, label the X and Y axis, and put a point at (1,5). Now simply turn the entire paper clockwise 90 degrees. If you do this, you'll see that what was the X axis is now the Y axis. And what was the Y axis is now the X axis. Label the axis again, and read the location of the point you marked. If you do so, you'll see that you have to go 5 spaces along the X axis, hence the 5. And you'll go 1 space down on the Y axis, hence the -1. So the coordinates of W(1,5) rotated 90 degrees clockwise around (0,0) changes to (5,-1).</span>
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8

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the one that the number has are the same is the data

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4 years ago
Solve for x. PLZ WAIT FOR PHOTO
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7 0
3 years ago
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Determine mABDarc using the appropriate theorems and postulates.<br> !please no absurd answers! : )
torisob [31]

Answer:

  arc ABD = 56°

Step-by-step explanation:

The measure of arc EF is the same as the measure of central angle ECF. That angle is a vertical angle with angle ACB, so they are congruent. The angle sum theorem tells you the measure of angle ACD is the sum of the measures of angles ACB and BCD. That sum is 35° +21° = 56°.

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4 0
3 years ago
Listed below are the number of years it took for a random sample of college students to earn bachelor's degrees (based on data f
schepotkina [342]

Answer:

a) Mean = 6.5, sample standard deviation = 3.50

b) Standard error = 0.7826

c) Point estimate = 6.5

d) Confidence interval:  (5.1469 ,7.8531)

Step-by-step explanation:

We are given the following data set for students to earn bachelor's degrees.

4, 4, 4, 4, 4, 4, 4.5, 4.5, 4.5, 4.5, 4.5, 4.5, 6, 6, 8, 9, 9, 13, 13, 15

a) Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{130}{20} = 6.5

Sum of squares of differences = 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 4 + 4 + 4 + 4 + 4 + 4 + 0.25 + 0.25 + 2.25 + 6.25 + 6.25 + 42.25 + 42.25 + 72.25 = 233.5

S.D = \sqrt{\frac{233.5}{19}} = 3.50

b) Standard Error

= \displaystyle\frac{s}{\sqrt{n}} = \frac{3.50}{\sqrt{20}} = 0.7826

c) Point estimate for the mean time required for all college is given by the sample mean.

\bar{x} = 6.5

d) 90% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729  

6.5 \pm 1.729(\frac{3.50}{\sqrt{20}} ) = 6.5 \pm 1.3531 = (5.1469 ,7.8531)

e) No, the confidence interval does not contain the value of 4 years. Thus, confidence interval is not a good estimator as most of the value in the sample is of 4 years. Most of the sample does not lie in the given confidence interval.

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4 years ago
6 is what percent of 9?
mario62 [17]

Answer:

66.6666666666666666%

6 0
3 years ago
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