Answer:
11200 for 7 engines for a total of 80 hours
Step-by-step explanation:
You have 8 engines burning 12000 .for 10 hours.
Divide 10 hours into 12000=1200 PER hour.
1200 ÷8 engines = 140 per hour per engine.
140 × # of hours (12)=1680 for 12 hours per engine.
# of engines × 1680 for 12 hour/per engine
5×1680 = 8400 of fuel for 12 hours/5 engine
Then you have 2 that runs 10 hours
2 × 140 per hour per engine =280 × 10 =2800 for 2 engines for 10 hours
8400. + 2800= 11200 of fuel for 6 engines
Answer:
Step-by-step explanation:
w^3 + 4w^2 + 5w - 12
What is the mode of this data set? 35,36,35,38,37,38,38,38,33,40,34,36,36,38,39,38,37,33,37,38,36,32,36,37,32
denpristay [2]
Answer:
38
Step-by-step explanation:
The most occuring number is the mode, which in this case is 38.
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