Answer:
A sample size of 1031 is required.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is of:

37% of freshmen do not visit their counselors regularly.
This means that 
98% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?
A sample size of n is required.
n is found when M = 0.035. So






Rounding up:
A sample size of 1031 is required.
Prime Factorization of 900= 2, 2, 3, 3, 5, 5
Prime Factorization of 212= 2, 2, 53
It would be 2/5 but the numbers between is 2/10 and 3/10
33+9= 42+12= 54+2=90-56= 34 34+3x
I don't know