I would say, well, if there are 3 sides that are equal on spinner 1. They are equal. But, we are focusing on spinner two that has two sides. If there is only 2 equal sides then, they would have to be straight across from each other. So that is 180. 360 is full circle. take away 180 to get answer.
360-180=180
I hope this helped. And sorry if it is not the correct answer. But that is how I would of answered it
Answer:
(a) scalene, see attachment
(b) acute, see attachment
(c) correct; isosceles
Step-by-step explanation:
(a) The sides of the triangle all have different lengths, so the triangle is scalene. Differences in coordinates between the points of the triangle are (6, 2), (5, 2), and (4, 1), so no two distances between these points can be the same.
__
(b) The angle opposite the longest side is clearly an acute angle, so the triangle is an acute triangle.
__
(c) Miles and Brad live on the same north/south line. Jose lives at a distance that is halfway between those houses in the north-south direction. Hence the distance to Miles' and Brad's houses must be the same from Jose's house. That means the triangle connecting Miles', Brad's, and Jose's houses will be an isosceles triangle.
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
6 × 2 = 12 so 6 is the dilation factor
thus 4 × 6 is PQ which is 24
