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lisabon 2012 [21]
2 years ago
12

How do I do functions with graphs?

Mathematics
1 answer:
levacccp [35]2 years ago
3 0

Answer:

the function would by labeled y

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a taste test asks people from Texas and California which pasta they prefer, brand A or brand B. this table shows the results
ELEN [110]

Answer:

D.

Step-by-step explanation:

Two events A and B are independent when

P(A|B)=P(A),

where P(A|B) is the probability that event A occurs given that event B has occured.

A = randomly selected person is from California

B = randomly selected person preferred brand A

A|B =  being a person from California and preferring brand A.

Hence,

P(A)=\dfrac{150}{275}=\dfrac{6}{11}\approx 0.55\\ \\P(B)=\dfrac{176}{275}=\dfrac{16}{25}=0.64\\ \\P(A|B)=\dfrac{96}{176}=\dfrac{6}{11}\approx 0.55

Since  P(A)=P(A|B), events are independent.

4 0
2 years ago
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12c - 4 = 14c - 10<br><br> c = ?<br><br> !!!
Sergio [31]
The answer to this question is c=3

3 0
3 years ago
Can someone please help me with number 6?
Vlad1618 [11]

Step-by-step explanation:

substitute a with 2 and b with 3

2x+3

because it's the same equation it should just be an equal sign.

8 0
1 year ago
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A circle has a sector with area 33 pi and a central angle of 11/6 pi radians. What is the area of a circle?
Mashutka [201]

Answer:

36π

Step-by-step explanation:

The area of a circle is given as:

A = \pi r^2

where r = radius of the circle

The area of a sector of a circle is given as:

A_s = \frac{\alpha }{2\pi} * \pi r^2

where α = central angle in radians

Since \pi r^2 is the area of a circle, A, this implies that:

A_s = \frac{\alpha }{360}  * A

A circle has a sector with area 33 pi and a central angle of 11/6 pi radians.

Therefore, the area of the circle, A, is:

33 \pi = \frac{\frac{11 \pi}{6} }{2 \pi} * A\\\\33\pi = \frac{11}{12} * A\\\\=> A = \frac{33\pi * 12}{11}\\ \\A = \frac{396 \pi}{11} \\\\A = 36\pi

The area of the circle is 36π.

5 0
2 years ago
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An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes. The results wer
liraira [26]

Step-by-step explanation:

since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1

So probabaility for \mathrm{X}=1 is

P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679

So expected frequency for X=1 is 0.3679^{*} 30=11.037 (or \left.11.04\right) .

8 0
3 years ago
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