n(A-B) denotes elements which are in A but not in B
n(Au B) denotes elements in A and B
n(AnB) denotes elements that are common in A and B
Now I will add one more set
n(B-A) which denotes elements in B but not in A
So, n(AuB) = n(A-B) + n( B-A) +n(AnB)
70 = 18 +n(B-A) + 25
70 = 43 + n(B-A)
n(B-A) = 70-43
n(B-A) = 27
So, n(B) = n( B-A) + n( AnB)
= 27+25
= 52
Answer:
£160
Step-by-step explanation:
Ammount he receives per year times 4.
800 x 0.05 x 4
= £160
It must be ≤ instead of ≥.
y ≤ - 3·x + 4
0.9 is the answerrrrrrrrrrrrrr
Answer:
i cant see the link try reposting
Step-by-step explanation: