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seraphim [82]
2 years ago
11

What is a formula for the nth term of the given sequence? -7, -12, -17...

Mathematics
1 answer:
goldenfox [79]2 years ago
3 0
22 should be the answer because it’s deducting 5 each time
You might be interested in
Simplify  ( √ 5 ) ( 3 √ 5 )
Amiraneli [1.4K]

Answer:

5^\frac{5}{6}

Step-by-step explanation:

\sqrt{5} can be represented as 5^{\frac{1}{2}} and \sqrt[3]5} can be represented as 5^{\frac{1}{3}}. Therefore, the expression can be rewritten as:

5^{\frac{1}{2}}*5^{\frac{1}{3}}

The rule for multiplying two exponents with the same base is you add the exponents. For example: x^m*x^k=x^{m+k}

We can use the same property to get:

5^{\frac{1}{2} +\frac{1}{3}}

which is just 5^\frac{5}{6} after you add the fractions

8 0
3 years ago
What is the interquartile range of this set of data? 15, 19, 20, 25, 31, 38, 41
Irina18 [472]
First, you have to find the median, which is the number in the middle: 25

Then cut the data in half by the median, so your new data sets are
15,29,20
    and 
31,38,41

Now you find the median of both of those sets, which is 29 and 38.

The interquartile range is the difference between the numbers, so 38-29 = 9.
8 0
3 years ago
Sorry another question!
Julli [10]

Answer:

you start counting from left to right

when you want to calculate the difference you have to choose two numbers that are next to each other and subtract second one from first one and because the different between every 2 numbers in order are the same numbers we call it a common difference.

Step-by-step explanation:

for example for 4 :

1. we can choose two numbers next to each other like 1 and 1.1

2. subtract second from first like 1.1 - 1 = 0.1

3. 1.1 + 0.1 = 1.2

1.2 + 0.1 = 1.3

and ...

so the common difference is 0.1

8 0
3 years ago
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
What is the simplest form of the radical expression?
BaLLatris [955]
I believe the equation is
4 \sqrt[4]{2x} + 6  \sqrt[4]{2x}
In this case, you would simplify it by adding them together.
4 \sqrt[4]{2x} + 6  \sqrt[4]{2x} = 10  \sqrt[4]{2x}
And can even be changed to an exponential equation:
10(2x)^{ \frac{1}{4} }
7 0
3 years ago
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