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11Alexandr11 [23.1K]

3 years ago

10

A company that makes hair-care products had 2,000 people try a new shampoo. Of the 2,000 people, 4 had a mild allergic reaction.

What percent of the people had a mild allergic reaction?

1 answer:

bazaltina [42]3 years ago

4 0

Answer:

0.2%

Step-by-step explanation:

2,000 people tested the new shampoo.

4 people had a mild allergic reaction.

4 is what percentage of 2,000?

0.2 percent.

(2,000 = %99.8)

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The value of a car is 18,500. It loses 10.3% of its value every year. Find the approximate monthly decrease in value. Round your

valentina_108 [34]

Answer:

$158.8

Step-by-step explanation:

There are 12 months in 1 year.

If in 1 year, it looses value of 10.3%, so in a month it will loose value of:

10.3%/12 = 0.8583% per month

So, to find the decreased value (in dollars) per month, we got to find 0.8583% of 18,500 dollars.

First, we need to convert percentage to decimal by dividing by 100. Then we multiply that to 18,500 to get our answer. So:

0.8583% = 0.8583/100 = 0.008583

Now,

0.008583 * $18,500 = $158.7855

Rounded to nearest tenth (1 decimal pae) = $158.8

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3 years ago

If g(x) = -2x+7, what is the new function defined by h(x) = g(2x^2 +1)

hammer [34]

Answer:

h(x) = - 4x² + 5

Step-by-step explanation:

To find h(x) = g(2x² + 1), substitute x = 2x² + 1 into g(x)

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4 years ago

For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l

murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

$X_i \sim \frac{G_1}{2}$

$E(X_i)=2 \\$

$Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\$

$= \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2$

Now we calculate the $\bar X \sim N(2, \sqrt{\frac{2}{n}})\\$

$\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}} \sim N(0, 1)\\$

$\to \sum^n_{i=1} \frac{X_i - 2}{n} \times\sqrt{\frac{n}{2}}} \sim N(0, 1)\\\\\to \sum^n_{i=1} \frac{X_i - 2}{\sqrt{2n}} \sim N(0, 1)\\$

$\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\$

$\to P(-1 \leq X_n \leq 2) = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\$

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kotykmax [81]

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Step-by-step explanation:

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