The equation of the line that passes through the point (4,-4) and has a slope of -3 is y = -3x + 8.
<h3>How to find the equation of a line?</h3>
The equation of a line can be represented in slope intercept form as follows:
y = mx + b
where
Therefore, the equation of the line that passes through the point (4,-4) and has a slope of -3 can be found as follows;
m = -3
Hence,
y = -3x + b
using (4, -4) let's find the y-intercept.
-4 = -3(4) + b
-4 = - 12 + b
b = -4 + 12
b = 8
Therefore, the equation is y = -3x + 8
learn more on equation of a line here: brainly.com/question/29472392
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It's the same as the 1st one
Answer:
x = StartFraction negative
(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction
Step-by-step explanation:
0 = – 3x2 – 2x + 6
It can still be written as
– 3x2 – 2x + 6 =0
Quadratic formula=
-b+or-√b^2-4ac/2a
Where
a=-3
b=-2
c=6
x= -(-2)+ or-√(-2)^2-4(-3)(6)/2(-3)
x = StartFraction negative
(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction
Add all the numbers up but pay attention you are counting 6.30 twice. then you divide by the numbers of days you have.(5)
<span>Your answer should be 5.47</span>
