Answer:
x = 53
y = 30
Step-by-step explanation:
Step(I):-
Given equations are
x -2y =-7 ...(I)
5x-9y =-5 ..(ii)
The matrix form AX = B
![\left[\begin{array}{ccc}1&-2\\ 5 & -9\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}-7\\-5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%5C%5C%205%20%20%26%20-9%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-7%5C%5C-5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The determinant

By using Cramer's Rule
Δ₁ =
The determinant is Δ₁ = -9 X -7 - (10 ) = 53
x = Δ₁ / Δ
x = 53
The determinant
Δ₂ =
Δ₂ = -5 +35
y = Δ₂/Δ = 30
That would be 16(1/4)^(n-1)
for example 4th term = 16(1/4)^3 = 1/4
1. X = 14
2. X = 120
3. X = 9.24
4. X = 16
5. X = 193.6
6. X = 11
7. X = 7.8
8. X = 446.4
9. X = 26.25
10. X = 6.6
11. X = 9
12. X = 2.01
Answer:
linear functions will create a straight line when graphed but if you were to graph a non linear equation then it would not create a straight line
Step-by-step explanation: