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umka21 [38]
2 years ago
10

Evaluate 4 divided by 5/6

Mathematics
1 answer:
allochka39001 [22]2 years ago
8 0

Answer:

4.8

Step-by-step explanation:

brainliest plsssssss

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Can someone pls help me<br> Pls
lora16 [44]

Answer:

help u with what? Say what u need

5 0
2 years ago
Sherman has 3 cats and 2 dogs. he wants to buy a toy for each of his pets. Sherman has 22$ to spend on pet toys. How much can he
WARRIOR [948]

Sherman wants to spend on each pet, so we are assuming he wants to spend the same amount. He has 5 pets in all (3 cats, 2 dogs)

Divide 22 with 5

22/5 = 4.4

He can spend $4.40, or in fraction form:

4 4/10 (Mixed fraction)

hope this helps

6 0
3 years ago
Which is a quadratic function
vfiekz [6]

According to Google:

In algebra, a quadratic function, a quadratic polynomial, a polynomial of degree 2, or simply a quadratic, is a polynomial function in one or more variables in which the highest-degree term is of the second degree.

If this is a homework question, just paraphrase!

4 0
3 years ago
Solve the equation below.<br><br> 1.2m+0.65=5
andrew-mc [135]

Answer:

m = 3.625

Step-by-step explanation:

1.2m + 0.65 = 5

~Subtract 0.65 to both sides

1.2m = 4.35

~Divide 1.2 to both sides

m = 3.625

Best of Luck!

5 0
3 years ago
The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1
Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let r represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

\frac{dr}{dt}=7\ mm/hr

Volume of cylinder is given by:

V=\pi\ r^2h

Finding derivative of the Volume with respect to time.

\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}

Plugging in the values given:

\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)

\frac{dV}{dt}=252\pi

Using \pi=3.14

\frac{dV}{dt}=252(3.14)

\frac{dV}{dt}=791.28\ mm^3/hr (Answer)

Thus rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

6 0
2 years ago
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