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3 years ago

10

There are 50 animals in a shelter. Sixty percent of the animals are dogs. Which equation can be used to find the number of dogs

in the shelter?

1 answer:

prisoha [69]3 years ago

6 0

Answer:

sixty percent of 50 is 30. So i would say the first one. 30 dogs out of 50 animals.

Step-by-step explanation:

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Write a paragraph. How do you prepare fore a math test?

Alik [6]

Answer:

studying

Step-by-step explanation:

to prepare for a math test you have to study and study then have some one one to help you with it

4 0

3 years ago

Please I have my final now can someone help me with this fast

Mariana [72]

Answer:

option B

Step-by-step explanation:

Given :

$y = \frac{2}{3}x + 3\\\\y = \frac{5}{2}x + \frac{7}{2}\\\\$

Step 1 : simplify the equation :

$3y = 2x + 9\\\\2y = 5x + 7\\$

Step 2: Arrange the terms :

$2x - 3y = - 9\\\\5x -2 y = -7$

Step 3 : Solve for x and y :

2x - 3y = - 9 ------ ( 1 )

5x - 2y = - 7 --------- ( 2 )

_____________________

( 1 ) x 5 => 10x - 15y = - 45 ---------- (3 )

( 2) x 2 => 10x - 4y = - 14 ----------- (4 )

_______________________

( 3 ) - ( 4 ) => 0x - 11y = - 31

- 11 y = - 31

$y = \frac{31}{11}$

Substitute y in ( 1 ) :

2x - 3y = - 9

$2x - 3 (\frac{31}{11}) = - 9\\\\2x = -9 + 3(\frac{31}{11})\\\\2x = - 9 + \frac{93}{11}\\\\2x = \frac{-99 + 93}{11} \\\\2x = \frac{-6}{11} \\\\x = \frac{-6}{2 \times 11} = -\frac{3}{11}$

Therefore the solution to the sytem is $( - \frac{3}{11} , \frac{31}{11})$

The solution of the system of equation is a point which lies

on the both the lines.

Option A : False , It says the solution lies above one of the given line.

But the solution of the system of equation always lies on

both the line.

Option B : True , says the solution is a point on the coordinate plane.

Option C : False, because if the solution is on the x-axis , then

the y coordinate in the solution would be zero.

But it is not zero.

Option D : False , the solution is the point where both the lines intersect.

8 0

3 years ago

Find the velocity and position vectors of a particle that has the given acceleration and the given initial velocity and position

stira [4]

Answer:

$v(t) = (2t+1) \mathbb{i} +3t^2 \mathbb{j} +4t^3 \mathbb{k}$

$r(t) = (t^2+t) \mathbb{i} +(t^3+2) \mathbb{j} +(t^4 - 3) \mathbb{k}$

Step-by-step explanation:

The velocity vector is the integral of the acceleration vector i.e.

$v(t) = \int a(t) dt$

$v(t) = \int (2 \mathbb{i}+6t \mathbb{j} 12t^2 \mathbb{k}) dt$

$v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + C_1$

When $t=0$ , $v(0) = \mathbb{i}$ . Inserting these values in $v(t)$ ,

$C_1= \mathbb{i}$

$v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + \mathbb{i}$

$v(t) = (2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}$

The position vector is the integral of the velocity vector i.e.

$r(t) = \int v(t) dt$

$r(t) = \int ((2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}) dt$

$r(t) = (t^2+t) \mathbb{i}+t^3 \mathbb{j} t^4 \mathbb{k} + C_2$

When $t=0$ , $r(t) =2\mathbb{j}-3\mathbb{k}$ . Inserting these values in $r(t)$ ,

$C_2=2\mathbb{j}-3\mathbb{k}$

$r(t)= (t^2+t) \mathbb{i}+t^3 \mathbb{j}+ t^4 \mathbb{k} + 2\mathbb{j}-3\mathbb{k}$

$r(t) = (t^2+t) \mathbb{i}+(t^3+2) \mathbb{j}+ (t^4-3) \mathbb{k}$

5 0

4 years ago

Can someone help me with this

Angelina_Jolie [31]

Answer:

10

Step-by-step explanation:

Since 75 sandwiches have salad this means that 75 - 30 = 45 of them have tuna with salad. Therefore, the amount of sandwiches that have cheese without salad is 100 - (30 + 15 + 45) = 100 - 90 = 10.

7 0

3 years ago

Solve the linear equation by using the Gauss-Jordan elimination method

Paha777 [63]

Answer: ( x , − x/ 3 − 5 /3 )

Step-by-step explanation:

7 0

4 years ago