All categories

2 years ago

Given the function w (x) = 9x + 8, evaluate w (5) . Explain all steps.

Mathematics

2 answers:

masya89 [10]2 years ago

7 0

Hi there!

$\large\boxed{w(5) = 53}$

Evalute by substituting in 5 for x:

w(5) = 9(5) + 8

Simplify:

w(5) = 45 + 8 = 53

ddd [48]2 years ago

6 0

Answer:

Step-by-step explanation:

by replacing 5 in the place of x we get 45+8= 53

You might be interested in

Aaron has 5 dimes and 2 nickels. how much money does Aaron have?

Doss [256]

Knowing that one dime has a 10 cent value and that a nickle has a 5 cent value, we can use multiplication or addition to find the answer.

5 x 10 = 50 5 dimes together are worth 50 cents.

2 x 5 = 10 2 nickles together are worth 10 cents.

50 + 10 = 60 5 dimes and 2 nickles are worth 60 cents when added together.

ANSWER: Aaron has 60 cents.

7 0

3 years ago

Read 2 more answers

Kristen and melissa spent 35% of their $32 on movie tickets. how much money did they spend

Ostrovityanka [42]

Answer:

11.2$

Step-by-step explanation:

Kristina and Melissa had 32$ at total

● 32$ => 100%

They have spent 35%

Let x be that amount

● x => 35%

●32 => 100

● x => 35

● x = (35×32)/100 = 11.2$

They have spent 11.2$

3 0

2 years ago

Read 2 more answers

B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =

jolli1 [7]

I suppose you mean

$g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)$

Differentiate one term at a time.

Rewrite the first term as

$\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}$

Then the product rule says

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'$

Then with the power and chain rules,

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}$

Simplify this a bit by factoring out $\frac12 (36-x^2)^{-3/2}$ :

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}$

For the second term, recall that

$\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}$

Then by the chain rule,

$\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}$

So we have

$g'(x) = 18 (36-x^2)^{-3/2} + 18 (36-x^2)^{-1/2}$

and we can simplify this by factoring out $18(36-x^2)^{-3/2}$ to end up with

$g'(x) = 18(36-x^2)^{-3/2} \left(1 + (36-x^2)\right) = \boxed{18 (36 - x^2)^{-3/2} (37-x^2)}$

5 0

2 years ago

The function f(x) = 1/3x + 5 and g(x) = x^2 + 4x are shown graphed below. The negative solution to the equation f(x) = g(x) is c

sergij07 [2.7K]

Answer:

Step-by-step explanation:

4 0

2 years ago

The governor of state A earns 50, 440 more than the governor of state B. If the total of their salaries is $283,910, can you fin

WITCHER [35]

Use what we know to make equations in order to solve for each governor's salary.
A=governor of state A
B=governor of state B
A+b=283,910. (Their salaries combined)
A=B+50,440 (A earns 50,440 more than B)
Sub A into the original formula to solve for B
B+50,440+b=283,910
2B=283,910-50,440
2B=233,470
B=116,730
Sub B into the formula that's equal to A
A=B+50,440
A=116,735+50,440
A=167,175
I hope this helps!

4 0

3 years ago