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3 years ago

Pleasee help me, it says evaluate the numerical expressions. decide whether they are equivalent, what’s the value of 84 - 14

Mathematics

1 answer:

Rainbow [258]3 years ago

3 0

Boi are you asking what’s 84-14??

It’s 74

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Maurinko [17]

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3 years ago

Which points are coplanar and noncollinear

yaroslaw [1]

Answer:

Non-collinear points: These points, like points X, Y, and Z in the above figure, don't all lie on the same line. Coplanar points: A group of points that lie in the same plane are coplanar. Any two or three points are always coplanar. Four or more points might or might not be coplanar.

Step-by-step explanation:

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3 years ago

-4 1/2 divided by - 2 2/3 as a mixed number

podryga [215]

Answer:

Exact Answer is 27/16

Decimal form: 1.6875

Mixed fraction 1 11/16 I assume that's what you need.

Step-by-step explanation:

27/16

Divide 27 by 16:

1 | 6 | 2 | 7

16 goes into 27 at most one time:

| | | 1

1 | 6 | 2 | 7

| - | 1 | 6

| | 1 | 1

Read off the results. The quotient is the number at the top and the remainder is the number at the bottom:

| | | 1 | (quotient)

1 | 6 | 2 | 7 |

| - | 1 | 6 |

| | 1 | 1 | (remainder)

The quotient of 27/16 is 1 with remainder 11, so:

Answer: 1 11/16

5 0

4 years ago

PLEASE ANSWER QUICK IT IS EASY!!!!!!!!!!!!! A student took 75 minutes to answer a combination of 30 multiple-choice and extended

GenaCL600 [577]

Answer:

What is the question? there is only statement.

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3 years ago

A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability

Hoochie [10]

Answer:

The probability of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

A city council consists of seven Democrats and five Republicans.
A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\times (n-k)!}$

Compute the number of ways to select four people as follows:

${12\choose 4}=\frac{12!}{4!\times (12-4)!}=495$

Compute the number of ways to selected two Democrats as follows:

${7\choose 2}=\frac{7!}{2!\times (7-2)!}=21$

Compute the number of ways to selected two Republicans as follows:

${5\choose 2}=\frac{5!}{2!\times (5-2)!}=10$

Then the probability of selecting two Democrats and two Republicans as follows:

$P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242$

Thus, the probability of selecting two Democrats and two Republicans is 0.4242.

6 0

3 years ago