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4 years ago

3,400,000 34,000 ---- 3.4 --- need pattern

Mathematics

1 answer:

vazorg [7]4 years ago

6 0

Each time you divide by 100. The pattern is 3,400,000 - 34,000 - 340 - 3.4 - 0.034

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What simplified ratio correctly compares 10,000 centimeters to 1000 meters?

zloy xaker [14]

10:1

Explanation: Divide 1000 meters by 1000 to decrease it to 1 so 10000 divided by 1000 is 10.

7 0

3 years ago

Read 2 more answers

Evaluate the series 72+12+2+

RUDIKE [14]

72+12=84
84+2=86
So add 72 plus 12 and you get Eighty-Four . Plus 2 equals 86

3 0

3 years ago

How many solutions does the following system have?

ale4655 [162]

Answer:

Option D. No solutions

Step-by-step explanation:

we have

$3x+2y=1$ -----> equation A

$-9x-6y=3$ ----> equation B

Multiply by -3 both sides equation A

$-3(3x+2y)=-3(1)$

$-9x-6y=-3$ -----> equation C

Compare equation B and equation C

Equation B and equation C are parallel lines with different y-intercept

Verify

For x=0

Equation C

$-9(0)-6y=-3$ -----> $y=0.5$

The y-intercept is the point (0,0.5)

Equation B

$-9(0)-6y=3$ -----> $y=-0.5$

The y-intercept is the point (0,-0.5)

therefore

Lines do not intersect

The system has no solution

see the attached figure to better understand the problem

6 0

4 years ago

The ratio 5/8 to 10/9 has a unit rate of 9/16 True or false

NemiM [27]

Answer:

This is false.

Step-by-step explanation:

The easiest thing to do is notice that 8 goes into 16 whilst 9 doesn't so that shows 9/16 would not be the unit rate.

3 0

3 years ago

Read 2 more answers

Among a group of 100 people, 68 can speak English, 45 can speak French, 42 can speak Spanish. 27 can speak both English and Fren

Nat2105 [25]

Answer:

Step-by-step explanation:

Given

No of People who can speak English is $n(E)=68$

No of People who can speak French is $n(F)=45$

No of People who can speak Spanish is $n(S)=42$

No of People who can speak both English and French $n\left ( E\cap F\right )=27$

No of People who can speak both English and Spanish $n\left ( E\cap S\right )=25$

No of People who can speak both French and Spanish $n\left ( F\cap S\right )=16$

No of people who can speak all languages is $n\left ( E\cap F\cap S\right )=9$

no of People who can Speak at least one Language is

$n\left ( E\cup F\cup S\right )=n\left ( E\right )+n\left ( F\right )+n\left ( S\right )-n\left ( E\cap F\right )-n\left ( E\cap S\right )-n\left ( F\cap S\right )+n\left ( E\cap F\cap S\right )$

$n\left ( E\cup F\cup S\right )=68+45+42-27-25-16+9=96$

Probability that Randomly selected can speak at least 1 of these languages

$P=\frac{96}{100}=0.96$

8 0

3 years ago