Answer:
C) The two populations will evolve into separate species.
Explanation:
In the given question, the population of animals has been split into two different populations due to a natural barrier present between them.
When we will observe these species after a very long time, the species will not be able to reproduce with each other and will be reproductively isolated. This reproductive isolation will lead to the formation of new species but belonging to the same genus.
Thus, Option-C is correct.
Answer:
they are nursed by their mothers
Explanation:
Answer:
0.25%
Explanation:
20 people start the new population. So there are 20 genes or 40 alleles for the recessive disorder phenylketonuria. 2 out of 40 alleles are recessive for the condition hence frequency of the allele = 2/40 = 0.05
Frequency of the allele does not change when the population increases so it is in Hardy-Weinberg equilibrium. According to it, if q is the frequency of recessive allele, q² = frequency of the recessive condition
Here, q = 0.05 So,
q² = (0.05)² = 0.0025
In percentage, it is 100 * 0.0025 = 0.25%
Hence, incidence of phenylketonuria in the new population is 0.25%
Homeostasis refer to the metabolic balance being maintained by several processes. It may include having a stable internal physiologic condition such as the blood ph or body temperature. Among the options, the best answer would be c. the villi of the small intestine would increase the absorption of nutrients from small intestine to the blood.
Answer: 2 in 4
Explanation: if the parents are both RB, one would end up red, one would end up blue, and 2 would be heterozygous and end up presenting the incompletely dominant color of purple.
