Answer:
All you have to do is substitute the value of x= -3 into the equation, then
g(-3) = -2(-3)2 + 3(-3) = -2(9) -9 = -18 - 9 = -27
Step-by-step explanation:
Answer: 20
Step-by-step explanation:
I suppose the figure that you do not include in your exercise is the one that I attached.
Looking at the figure, it is obvious that the angle COA is divided into two angles of 20 degrees each, so the answer would be 20.
The correct answer is: [B]: "40 yd² " .
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First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
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→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
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Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
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Now, we add the areas of BOTH the triangle AND the square:
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→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
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Answer: Choice A) The linear equation, aka straight line
Explanation:
The end behavior is determined by the ratio of the leading terms. This is because for large x values, the leading terms "drown out" (so to speak) the weight of the other terms.
We divide the leading terms 10x^3 over 2x^2 to get 5x. So as x gets really large, in either the positive or negative direction, the tail end portions will start to approach y = 5x. This is the slant or oblique asymptote. The end behavior or y = 5x has the left side going down, while the right side is going up. The same applies for the f(x) function as well.
