We have the following expression:
(x- (5/2)) ^ 2 = (13/4)
Let's rewrite the given expression:
x ^ 2 - 5x + 25/4 = (13/4)
x ^ 2 - 5x + 25/4 - 13/4 = 0
x ^ 2 - 5x + 12/4 = 0
x ^ 2 - 5x + 3 = 0
Answer:
the original equation given to Sam could have been:
x ^ 2 - 5x + 3 = 0
Answer:
144 children and 170 adults
Step-by-step explanation:
make 2 equations
make :
the children as the regarded as the variable : x
the adults are the regarded as the variable : y
<em>5x + 6 y = 1740</em>
<em>x + y = 314</em>
<h3><u>solve this by the method of elimination </u></h3>
5x + 6y = 1740
5(x + y = 314)
= 5x + 5y = 1570
5x + 6y = 1740
5x + 5y = 1570
the 5x is cancelled out
6y - 5y = 1740 - 1570
y = 170
now replace the value of y in the eqaution
5x + 6 (170) = 1740
5x =720
x = 144
hence they were 144 children and 170 adults
mark as brainiest
A^-b is the same as 1/a^b.
When there is a negative power, place the number and power over 1.
a^b/a^c = a^(b-c).
c is a negative power, because it is being divided, and is underneath b, which is a positive (and so it stays in the numerator).
a^c/b^c = (a/b)^c
Inside this one, the power of c is distributed to all numbers inside the parenthesis, in this case a and b.
hope this helps
